Question

Consider the reaction below. 2C6H14 + 19O2 Right arrow. 12CO2 + 14H2O How many moles of hexane (C6H14) must burn to form 18.4 mol of carbon dioxide?

Answer 1

Answer:

B)    3.07 mol

Explanation:

Answer 2

Answer:

$3.06mol~C_6H_14$

Explanation:

We have to start with the reaction:

$2C_6H_1_4 + 19O_2->12CO_2 + 14H_2O$

We have 2 carbons, 6 hydrogens and 38 oxygens on both sides.

Now the molar ratio between $C_6H_14$ and $CO_2$ is 2:12 or $2~mol~C_6H_14=~12~mol~CO_2$. With this  in mind we can calculate the moles of $C_6H_14$, so:

$18.4~mol~CO_2\frac{2~mol~C_6H_14}{12~mol~CO_2}=3.06mol~C_6H_14$

I hope it helps!