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kap26 [50]
3 years ago
12

Consider the reaction below. 2C6H14 + 19O2 Right arrow. 12CO2 + 14H2O How many moles of hexane (C6H14) must burn to form 18.4 mo

l of carbon dioxide?
Chemistry
2 answers:
daser333 [38]3 years ago
7 0

Answer:

B)    3.07 mol

Explanation:

sasho [114]3 years ago
6 0

Answer:

3.06mol~C_6H_14

Explanation:

We have to start with the reaction:

2C_6H_1_4 + 19O_2->12CO_2 + 14H_2O

<u>We have 2 carbons, 6 hydrogens and 38 oxygens on both sides</u>.

Now the <u>molar ratio</u> between C_6H_14 and CO_2 is 2:12 or 2~mol~C_6H_14=~12~mol~CO_2. With this  in mind we can calculate the moles of C_6H_14, so:

18.4~mol~CO_2\frac{2~mol~C_6H_14}{12~mol~CO_2}=3.06mol~C_6H_14

I hope it helps!

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Answer:

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Explanation:

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2 years ago
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2 years ago
List the substances Ar, Cl2, CH4, and CH3COOH, in order of increasing strength of intermolecular attractions. List the substance
Viefleur [7K]

Answer:

Order of increasing strength of intermolecular attraction:

CH_3COOH > Cl_2 > CH_4 > Ar

Explanation:

CH_3COOH can form hydrogen bond as H atom is attached with electronegative atom O.

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In non-polar molecules, van der Waal's intermolecular forces of attractions exist. Hydrogen bonding is stronger intermolecular attraction then van der Waal's intermolecular forces of attraction, hence, CH_3COOH has strongest intermolecular attractions.

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Therefore,

Order of increasing strength of intermolecular attraction will be:

CH_3COOH > Cl_2 > CH_4 > Ar

8 0
3 years ago
Read 2 more answers
Explain why, at room temperature, CO2 is a gas and CS2 is a liquid. You may use diagrams as part of your explanation.
eduard

Explanation:

A. Hydrogen bonding is present in CS2 but not in CO2.

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C. CS2 partly dissociates to form ions and CO2 does not. Therefore, ion-dipole interactions are present in CS2 but not in CO2.

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2 years ago
Draw all resonance structures for the nitryl fluoride molecule, no2f.
denis-greek [22]
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       F
 ..    I    ..
: O : N :O: 
 
              ..
     OR  : F:
              I                             

             N                                                  ..                                                                                                                                    : F:

          /         \                        or                   I

   ..                 ..                                               N

:O  :            :O:                                       / /        \\
                                                            / /               \\
                                                         :O :            :  O:
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3 years ago
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