Answer:
V2 = 35.967cm^3
Explanation:
Given data:
P1 = 0.2atm
P2 = 1.4atm
V1 = 250cm^3
V2 = ?
T1 = 10°C + 273 = 283K
T2 = 12°C + 273 = 285K
Apply combined law:
P1xV1/T1 = P2xV2/T2 ...eq1
Substituting values:
0.2 x 250/283 = 1.4 x V2/285
Solve for V2:
V2 = 14250/396.2
V2 = 35.967cm^3
Answer:
well what do you think it is
Explanation:
huh?..
Srry I can’t help u because I can’t understand ur English I don’t speak French Srry I’m learning French in school
You just have to find a conversion from amu to grams. For every 1 amu, there is 1.66×10⁻²⁴ grams. Thus,
Mass of proton = 1.0073 amu * 1.66×10⁻²⁴ grams/amu = 1.672×10⁻²⁴ grams
Since a proton is spherical in shape, the volume would be:
Volume = 1/6*πd³ = 1/6*π(1.0×10⁻¹⁵ cm)³ = 5.236×10⁻⁴⁶ cm³
Therefore, the density is equal to
Density = Mass/Volume = 1.672×10⁻²⁴ grams/5.236×10⁻⁴⁶ cm³
Density = 3.2×10²¹ g/cm³
Answer:
We can say, there are 4 mol of oxygen with (4 . NA) = 2.40ₓ10²⁴ atoms
Or just, 4 atoms oxygen.
Explanation:
CH₄ + 2O₂ → CO₂ + 2H₂O
1 mol of methane reacts with 2 mol of oxygen to produce 1 mol of carbon dioxide and 2 mol of water.
We count in 1 mol of CO₂, we have 2 mol of oxygen
In 2 mol of water, we have 2 mol of oxygen.
We can say, there are 4 mol of oxygen with (4 . NA) = 2.40ₓ10²⁴ atoms
Or just, 4 atoms oxygen.
