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2 years ago

7

If oxygen at 128 kpa is allowed to expand at constant temp until it's pressure is 101.3 kpa how much larger will the volume beco

me?

1 answer:

LenaWriter [7]2 years ago

6 0

which means that the volume increased by 26.4 mL in order to compensate for the decrease in pressure.

Like I said, depends on what your initial volume was, but that's how you think of it.

Hope this helped!

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3 years ago

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14.533 grams of solid precipitate of mercury(II) dichromate will form.

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$Hg(CH_3COO)_2(aq)+Na_2Cr_2O_7(aq)\rightarrow HgCr_2O_7(s)+2CH_3COONa(aq)$

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According to reaction , 1 mole of sodium dichromate reacts with 1 mole of mercury(II) acetate , then 0.045906 moles of sodium dichromate will recat with :

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According to reaction , 1 mole of sodium dichromate gives 1 mole of mercury(II) dichromate , then 0.045906 moles of sodium dichromate will give :

$\frac{1}{1}\times 0.045906 mol=0.045906 mol$ of mercury(II) dichromate

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3 years ago

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