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4 years ago

When one compound dissolves in water, the only positive ion produced in the solution is H3O+(aq). This compound is classified as

Chemistry

2 answers:

Mrac [35]4 years ago

5 0

Answer : The correct option is, (3) an Arrhenius acid

Explanation :

According to the Arrhenius concept, an acid is a substance which ionizes in the water to give hydronium ion $(H_3O^+)$ or hydrogen ion $(H^+)$ and a base is a substance which ionizes in the water to give hydroxide ion $(OH^-)$ .

When one compound dissolves in water, then only positive ion produced in the solution is $(H_3O^+)$ . This compound is classified as an Arrhenius acid.

Hence, the correct option is, (3) an Arrhenius acid

Lelu [443]4 years ago

3 0

When one compound dissolves in water, the only positive ion produced in the solution is (aq). This compound is classified as an Arrhenius acid.

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A4 g sugar cube (Sucrose : C 12 H 22 O 11 ) is dissolved in a 350 ml teacup of 80 C water. What is the percent composition by ma

lana66690 [7]

Answer:

%Sgr = 1% (1 sig.fig.)

Explanation:

mass water = 350ml x 0.975g/ml = 341.25g

mass sugar added = 4g

solution mass = 341.25g + 4g = 345.25g

%sugar = (4g/345.25g)·100% = 1.1586% ≅ 1% (1 sig.fig)

7 0

3 years ago

Need help !!!!! ASAP

Korolek [52]

<h2>Hello!</h2>

The answer is:

The new volume is 2.84 L.

$V_{2}=2.84L$

To solve the problem, we need to remember what STP means. STP means that the gas is at standard temperature and pressure, or 273.15 K (0°C) and 1 atm.

Also, we need to use the Combined Gas Law, since the temperature, the pressure and the volume are being changed.

The Combined Gas Law establishes a relationship between the temperature, the pressure and the volume of an ideal gas using , Gay-Lussac's Law, Charles's Law, and Boyle's Law.

The law is defined by the following equation:

$\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}$

Where,

$P_{1}$ is the first pressure.

$V_{1}$ is the first volume.

$T_{1}$ is the first temperature.

$P_{2}$ is the second pressure.

$V_{2}$ is the second volume.

$T_{2}$ is the second temperature.

So, we are given the following information:

$V_{1}=2L\\P_{1}=1atm\\T_{1}=0\°C=273.15K\\P_{2}=80kPa=0.8atm\\T_{2}=37\°C=37+273=310K$

Then, isolating the new volume, and substituting, we have:

$\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}\\\\V_{2}=\frac{P_{1}V{1}}{T_{1}}*\frac{T_{2}}{P_{2}}\\\\V_{2}=\frac{1atm*2L}{273.15K}*\frac{310K}{0.8kPa}=2.84L$

Hence, the new volume is 2.84 L.

$V_{2}=2.84L$

Have a nice day!

4 0

4 years ago

The saturation point for a solution is 50.0 grams of solute per 500 grams of solvent. How many grams of solute can be dissolved

-Dominant- [34]

Answer:

I think it can dissolve 80.0 grams

6 0

3 years ago

DNA has 2 strands. if the sequence of nucleotides of one strand was known, is it possible to use the information to determine th

ANTONII [103]

DNA has four main components.
Adenine=A
Cytosine=C
Guanine=G
Thymine=T

Since each letter has an opposite it would be possible by considering the pairs.
A:T
C:G

So, if one strand went as so:
AGCCTAGGTAC
The corresponding strand would be mirrored with the match: TCGGATCCTG

3 0

3 years ago

A 33.6 mL solution of KCl has a mass of 27.29 g. After evaporating to dryness, the dry salt residues has a mass of 6.31 g. Calcu

bixtya [17]

For the molarity and the percentage of the mass of kcl are mathematically given as

%m/m = 23.1%, molarity = 3.38M

<h3>What is the molarity?</h3>

Generally, the equation for the percentage of the mass of kcl is mathematically given as

(mass of kcl/mass of solution)x 100

therefore

%m/m = (6.31/27.29)x100

%m/m = 23.1%

The molarity

(no of mol/ vol of sol)

molarity = 0.0846mol/0.0250 L

molarity = 3.38M

In conclusion, the molarity is given as

molarity = 3.38M