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4 years ago

When one compound dissolves in water, the only positive ion produced in the solution is H3O+(aq). This compound is classified as

Chemistry

2 answers:

Mrac [35]4 years ago

5 0

Answer : The correct option is, (3) an Arrhenius acid

Explanation :

According to the Arrhenius concept, an acid is a substance which ionizes in the water to give hydronium ion $(H_3O^+)$ or hydrogen ion $(H^+)$ and a base is a substance which ionizes in the water to give hydroxide ion $(OH^-)$ .

When one compound dissolves in water, then only positive ion produced in the solution is $(H_3O^+)$ . This compound is classified as an Arrhenius acid.

Hence, the correct option is, (3) an Arrhenius acid

Lelu [443]4 years ago

3 0

When one compound dissolves in water, the only positive ion produced in the solution is (aq). This compound is classified as an Arrhenius acid.

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Choose all the answers that apply.

Tresset [83]

<h3>Answer:</h3>

#a.2H2 + O2 → 2H2O

#b. 2S + 3O2 → 2SO3

#d. 2K + 2H2O → H2 + 2KOH

<h3>Explanation:</h3>

A balanced chemical equation is one that has equal number of atoms of each element on both sides of the equation.

In this case;

2H2 + O2 → 2H2O - is balanced since it has, 4 hydrogen atoms and 2 oxygen atoms on either sides of the equation.
2S + 3O2 → 2SO3, is balanced. It has 2 sulfur atoms and 6 oxygen atoms on both side of the equation.
2K + 2H2O → H2 + 2KOH, is balanced , 2 potassium atoms, 4 hydrogen atoms and 2 oxygen atoms on both side of the equation.

On the other hand, the equations that are not balanced include;

Li + Cl2 → LiCl
2Fe + Cu(NO3)2 → 2Cu + Fe(NO3)2

This is because the number of atoms of each element is not equal on both side of the equation/

5 0

3 years ago

Read 2 more answers

Hyposulfite, SO22–, is a polyatomic ion that has not yet been definitively confirmed to exist. However, the VSEPR model may stil

LUCKY_DIMON [66]

Answer:

The most reasonable estimate for the O–S–O bond angle in hyposulfite = 106°

Explanation:

Hyposulphite (so₂²⁻) is polyatomic ion .

According to VSEPR model

Total elrctron pairs $=\frac{1}{2} [V+X -C+A]$

V = Valence shell electrons of central element

X = No. of monovalent surrounding atoms

C = Cationic charge

A = Anionic charge

Total electron pairs $=\frac{1}{2}[6+0-0+2]= 4$

That is two bond pairs and two lone pairs

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3 years ago

Giải phương trình phân tử và phương trình ion rút gọn<br> HCL+NaOH

Whitepunk [10]

Answer:

only japanese and english I understand sorry your languages

Explanation:

so sorry can you brainliest me pls I need Brainliest:)

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3 years ago

List three organelles found in cells and describe their functions.

kozerog [31]

nucleus: controls cell

cell membrane: controls what goes in and out of a cell

cytoplasm: where chemical reactions take place

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3 years ago

Read 2 more answers

A tank at is filled with of dinitrogen monoxide gas and of boron trifluoride gas. You can assume both gases behave as ideal gase

blsea [12.9K]

Answer:

(1). Mole fraction = 0.152 for sulfur tetrafluoride gas.

Mole fraction = 0.848 For dinitrogen monoxide gas.

(2). Partial Pressure for dinitrogen monoxide gas = 187 kPa

Partial Pressure for sulfur tetrafluoride gas = 33.4 kpa.

(3). Total Partial Pressure = 220.4 kpa.

Explanation:

So, we are given the following data or parameters or information in the question above;

• Volume of the tank = 5.00L per tank;

• Temperature of the tank = 7.03°C;

• The mass of the content in the tank =

17.7g of dinitrogen monoxide gas and

7.77g of sulfur tetrafluoride gas.

So, we will be making use of the formulae below to calculate the MOLE FRACTION:

Moles, n= mass/molar mass and mole fraction = n(1)/ n(1) + n(2) per each constituents.

Moles, n1 = 17.7g of dinitrogen monoxide gas/ 44 grams per mole. =0.4023 moles.

Moles, n2 = 7.77g of sulfur tetrafluoride gas/ 108.1 grams per mole. = 0.07188 moles.

Total numbers of moles = n1 + n2 = 0.47415 moles

Mole fraction =0.4023 / 0.47415 = 0.848 of dinitrogen monoxide gas.

Mole fraction = 0.07188/0.47415 = 0.152 of sulfur tetrafluoride gas.

PART TWO: CALCULATE THE PARTIAL PRESSURE AND TOTAL PRESSURE BY USING THE FORMULA BELOW;

pressure × volume = number of moles × gas constant, R × temperature.

Pressure = n × R × T/ V.

For dinitrogen monoxide gas. ;

Partial Pressure = 0.4023 × 8.314 × 280.03 / 5 × 10^-3 = 187 kPa.

For sulfur tetrafluoride gas

Partial Pressure = 0.07188 × 8.314 ( × 280.03 / 5 × 10^-3. = 33.4 kpa.

(3). Total pressure = (187 + 33.4)kpa = 220.4 kpa

6 0

3 years ago