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3 years ago

When one compound dissolves in water, the only positive ion produced in the solution is H3O+(aq). This compound is classified as

Chemistry

2 answers:

Mrac [35]3 years ago

5 0

Answer : The correct option is, (3) an Arrhenius acid

Explanation :

According to the Arrhenius concept, an acid is a substance which ionizes in the water to give hydronium ion $(H_3O^+)$ or hydrogen ion $(H^+)$ and a base is a substance which ionizes in the water to give hydroxide ion $(OH^-)$ .

When one compound dissolves in water, then only positive ion produced in the solution is $(H_3O^+)$ . This compound is classified as an Arrhenius acid.

Hence, the correct option is, (3) an Arrhenius acid

Lelu [443]3 years ago

3 0

When one compound dissolves in water, the only positive ion produced in the solution is (aq). This compound is classified as an Arrhenius acid.

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Can someone please help me with this Chem lab?

Jlenok [28]

Answer:

sooo dificult

Explanation:

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3 years ago

A scientist measures the standard enthalpy change for the following reaction to be 67.9 kJ:

bekas [8.4K]

Answer: The standard enthalpy of formation of $H_2O(g)$ is -252.1 kJ/mol.

Explanation:

The balanced chemical reaction is,

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

The expression for enthalpy change is,

$\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactantss}]$

Putting the values we get :

$\Delta H=[2\times H_f{Fe}+3\times H_f{H_2O}]-[1\times H_f{Fe_2O_3}+3\times H_f{H_2}]$

$67.9kJ=[(2\times 0)+(3\times H_f{H_2O})]-[(1\times -824.2kJ/mol)+3\times 0kJ/mol)]$

$H_f{H_2O}=-252.1kJ/mol$

Thus standard enthalpy of formation of $H_2O(g)$ is -252.1 kJ/mol.

3 0

2 years ago

Why is potassium less reactive than silver

Reika [66]

Because potassium is a gas that can evolve

3 0

2 years ago

Which of the following best explain how Earth's rotation affects direction of sunrise?

lozanna [386]

The rotation of the Earth causes sunlight to move from east to west and then it just keeps repeating it over and over again.

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3 years ago

Read 2 more answers

g Given that 50.0 mL of 0.100 M magnesium bromide reacts with 13.9 mL of silver nitrate solution according to the unbalanced equ

ipn [44]

Answer:

0.719M AgNO₃

Explanation:

Based on the reaction:

MgBr₂ + 2AgNO₃ ⇄ 2AgBr + Mg(NO₃)₂

<em>1 mole of magnesium bromide reacts completely with 2 moles of AgNO₃</em>

<em />

To find molarity of AgNO₃ solution we need to determine moles of AgNO₃ and, as molarity is the ratio of moles over liter (13.9mL = 0.0139L). Now, to determine moles of AgNO₃ we need to use the reaction, thus:

<em>Moles AgNO₃:</em>

<em />

Moles of MgBr₂ are:

50.0mL = 0.050L * (0.100mol / L) = 0.00500 moles of MgBr₂.

As the silver nitrate reacts completely and 2 moles of AgNO₃ reacts per mole of MgBr₂:

0.00500 moles MgBr₂ * (2 moles AgNO₃ / 1 mole MgBr₂) =

0.0100 moles of AgNO₃ are in the solution.

And molarity is:

0.0100 moles AgNO₃ / 0.0139L =

3 0

2 years ago