Since g(6)=6, and both functions are continuous, we have:
![\lim_{x \to 6} [3f(x)+f(x)g(x)] = 45\\\\\lim_{x \to 6} [3f(x)+6f(x)] = 45\\\\lim_{x \to 6} [9f(x)] = 45\\\\9\cdot lim_{x \to 6} f(x) = 45\\\\lim_{x \to 6} f(x)=5](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%206%7D%20%5B3f%28x%29%2Bf%28x%29g%28x%29%5D%20%3D%2045%5C%5C%5C%5C%5Clim_%7Bx%20%5Cto%206%7D%20%5B3f%28x%29%2B6f%28x%29%5D%20%3D%2045%5C%5C%5C%5Clim_%7Bx%20%5Cto%206%7D%20%5B9f%28x%29%5D%20%3D%2045%5C%5C%5C%5C9%5Ccdot%20lim_%7Bx%20%5Cto%206%7D%20f%28x%29%20%3D%2045%5C%5C%5C%5Clim_%7Bx%20%5Cto%206%7D%20f%28x%29%3D5)
if a function is continuous at a point c, then

,
that is, in a c ∈ a continuous interval, f(c) and the limit of f as x approaches c are the same.
Thus, since

, f(6) = 5
Answer: 5
Answer:
[See Below]
Step-by-step explanation:
❶ It is irrational because to make it repeating it must be <u>EXACT</u>. In this case it is adding a 0 after every 1. So it'd be irrational since it doesn't have an end.
❷ Irrational because no one knows the end of pi. It doesn't have an ending so therefore irrational.
~<em>Hope this helps Mate. If you need anything feel free to message me. </em>
Answer:
3(x + 4) = 3(x) + 3(4)
3(x + 4) = 3x + 12
3x + 12 = 3x + 12
Subtract 12 from both sides
3x + 12 - 12 = 3x + 12 - 12
3x = 3x
3x - 3x = 3x - 3x
= 0