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Alona [7]
3 years ago
11

Which port is used to transmit slow data over long distances?

Physics
1 answer:
lana66690 [7]3 years ago
5 0
The appropriate response would be serial port. This is a serial communication interface through which data goes in or out one piece at any given moment (as opposed to a parallel port). All through a large portion of the historical backdrop of PCs, information was exchanged through serial ports to gadgets, for example, modems, terminals, and different peripherals.
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A king has no sons, no daughters, and no queen. For this reason he must decide who will take the throne after he dies. To do thi
ZanzabumX [31]
The king gave them all fake seeds,  the little girl was the only honest child who didn't switch seeds.
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3 years ago
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which of the numbers on this figure indicates typical continental conditions (regional metamorphism)?
Tpy6a [65]

The number that indicates typical continental conditions (regional metamorphism) is that showing schist and gneiss rocks.

<h3>What is regional metamorphism?</h3>

Regional metamorphism occurs when rocks undergoes changes as a result of high temperatures and pressure deep within the earth's crust.

Regional metamorphic rocks are usually foliated or squashed in appearance.

Examples of regional metamorphism rocks are schist and gneiss rocks.

Therefore, the figure that indicates typical continental conditions (regional metamorphism) is that showing schist and gneiss rocks.

Learn more about regional metamorphism at: brainly.com/question/14678538

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4 0
2 years ago
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How long will it take a car to accelerate from 15.2 to 23.5 m/s if the car has an average acceleration of 3.2 m/s?
Nuetrik [128]
 a =  ( V2 - V1)/( t2 - t1)
 3.2 =  ( 23.5m/s - 15.2m/s)/(t - 0)
3.2m/s = 8.3/t
t(3.2) = 8.3
t = 8.3/3.2
t = 2.59 seconds
7 0
3 years ago
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I need help with 23 please.
Ne4ueva [31]
The answer is c.

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8 0
3 years ago
The size (radius) of an oxygen molecule is about 2.0 ×10−10 m. Make a rough estimate of the pressure at which the finite volume
timurjin [86]

Answer:

P = 1 x 10⁸ Pa

Explanation:

given,

radius = 2.0 ×10⁻¹⁰ m

Temperature

T = 300 K

Volume of gas molecule =

V = \dfrac{4}{3}\pi r^3

V = \dfrac{4}{3}\pi (2\times 10^{-10})^3

 V = 33.51 x 10⁻³⁰ m³

we know,

P  V = 1 . k T

k = 1.38  x 10⁻²³ J/K

P(33.51 x 10⁻³⁰) = 1 . (1.38  x 10⁻²³) x 300

P = 1.235 x 10⁸ Pa

for 1 significant figure

P = 1 x 10⁸ Pa

6 0
3 years ago
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