Answer:
the period of the 16 m pendulum is twice the period of the 4 m pendulum
Explanation:
Recall that the period (T) of a pendulum of length (L) is defined as:

where "g" is the local acceleration of gravity.
SInce both pendulums are at the same place, "g" is the same for both, and when we compare the two periods, we get:

therefore the period of the 16 m pendulum is twice the period of the 4 m pendulum.
Probably because of the drag coefficient and the density of the liquid.
The power in horsepower is 40.1 hp
Explanation:
We start by calculating the work done by the airplane during the climb, which is equal to its change in gravitational potential energy:

where
mg = 11,000 N is the weight of the airplane
is the change in height
Substituting,

Now we can calculate the power delivered, which is given by

where
is the work done
is the time taken
Substituting,

Finally, we can convert the power into horsepower (hp), keeping in mind that

Therefore,

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As this happens over twelve seconds, you would take the total difference in velocities and divide it by twelve to find the change per second
44.0 m/s - 2.0 m/s = 42.0 m/s
42.0 m/s / 12 s = 3.5 m/s2
the acceleration of the rock would be 3.5 m/s2