-- During the time the ball is flying from the high roof to the low roof,
it's going to fall (100-25) = 75 meters.
How long does it take an object dropped from rest to fall 75 meters ?
Distance = (1/2) · (gravity) · (time)²
75 m = (4.9 m/s²) · (time)²
Time² = (75 m) / (4.9 m/s²)
Time² = 15.31 sec²
Time = √(15.31 sec²) = 3.91 seconds
So the ball has to cover the horizontal distance of 20 meters
in 3.91 seconds.
Distance = (speed) · (time)
20 m = (speed) · (3.91 sec)
Speed = (20 m) / (3.91 sec)
Speed = 5.11 m/s
Answer:
4050 gallons
Explanation:
In first half and hour both pumps are working property . There for it give, 45
gallons per minute . Half and hour is equal to 30 minutes.After one pump was broken only one pump is working 30 minutes .
For 1st 30 minutes ,( 2 pumps are working )
Gallons = 45 * 30 *2 = 2700 gallons
2nd 30 minutes ( 1 pump is working )
Gallons = 45*30*1 = 1350 gallons
Total gallons = 2700+1350
= 4050 gallons
If an initial cardioversion attempt is unsuccessful in a 33-pound child, you should repeat the procedure using 30 joules.
Cardioversion
Cardioversion is a medical therapy that uses medications or electricity to restore a normal heart rhythm to someone who has an abnormally high heart rate (tachycardia) or another cardiac arrhythmia. Synchronized electrical cardioversion restores the activity of the heart's electrical conduction system by applying a therapeutic dosage of electric current to the heart at a specified point in the cardiac cycle. (Defibrillation is the most efficient form of resuscitation for cardiac arrest caused by ventricular fibrillation and pulseless ventricular tachycardia. It delivers a therapeutic dosage of electric current to the heart at an unpredictable point in the cardiac cycle. Chemical cardioversion, also known as pharmacologic cardioversion, substitutes antiarrhythmic drugs for an electrical shock.
To learn more about cardioversion refer here:
brainly.com/question/11601470
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Answer:
A
Explanation:
Frequency is defined by repetitions or periods per second. If we take any segment from each graph, we would see that graph A has the most repetitions per second.
The period of A is the shortest since the frequency is equal to 1/T, the smaller the period, the higher the frequency.