Answer:
Cathode: Ag
Anode: Br₂
Explanation:
In the cathode must occur a reduction, so it's more likely to a metal atom be in the cathode. For the metals given the reduction reactions and the potential of reduction are:
Ag⁺ + e⁻ ⇒ Ag⁰ E° = + 0.80 V
Fe⁺² + 2e⁻ ⇒ Fe⁰ E° = - 0.44 V
Al⁺³ + 3e⁻ ⇒ Al⁰ E° = -1.66 V
As the potential for Ag is the higher, the reduction will occur for it first, so in the cathode will produce Ag.
For the anode an oxidation must occurs, so the reactions for the nonmetals are:
F₂ + 2e⁻ ⇒ 2F⁻ E° = +2.87 V
Cl₂ + 2e⁻ ⇒ 2Cl⁻ E° = +1.36 V
Br₂ + 2e⁻ ⇒ 2Br⁻ E° = +1.07 V
For oxidation, the less the E°, the faster the reaction will occur, so Br₂ will be formed in the anode.
Answer: The boiling point of a 3.70 m solution of phenol in benzene is 
Explanation:
Elevation in boiling point:
where,
= change in boiling point
i= vant hoff factor = 1 (for benzene which is a non electrolyte )
= boiling point constant = 
m = molality = 3.70
Thus the boiling point of a 3.70 m solution of phenol in benzene is
Answer:
1- d= m/v d=540/200 d=2,7 g/cm
Explanation:
Answer:
Rotate the types of drops grown
Explanation:
