I think I it’s gonna be C.
Let's note that 1 pint = 473.1765 mL, so 11 pints should be 5204.9415 mL.
We make a proportion out of the word problem
(85 mg glucose/ 100 mL) times (1 g/ 1000 mg) = 4.4242 grams of glucose
The formula will be AI2O3
Capture all of the smoke and weight it. it will weigh exactly the same before and after you burn it but will just be CO2 and H2O gas.
Answer: I would say its either exit door or the last one.
Explanation: Hope this helps plz mark brainliest.
