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mamaluj [8]
3 years ago
10

For an atoms electrons, how many energy sub levels are present in the principal energy level n=4?

Chemistry
1 answer:
kupik [55]3 years ago
7 0

A. 4. There are four sublevels in the n=4 level.

They are the <em>4s, 4p, 4d</em>, and <em>4f</em> sublevels.


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Which of the following are pure substances? (Select all that apply.)
riadik2000 [5.3K]
Elements and compounds are both examples of pure substances. Compounds are substances that are made up of more than one type of atom. Elements are the simplest substances made up of only one type of atom. i hope that helps:)
6 0
2 years ago
The characteristic odor of pineapple is due to ethyl butyrate, a compound containing carbon, hydrogen, and oxygen. Combustion of
gavmur [86]

<u>Answer:</u> The empirical formula for the given compound is C_3H_6O

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Conversion factor:  1 g = 1000 mg

Mass of CO_2=6.32mg=0.00632g

Mass of H_2O=2.58g=0.00258g

Mass of compound = 2.78 mg = 0.00278 g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

  • <u>For calculating the mass of carbon:</u>

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 0.00632 g of carbon dioxide, \frac{12}{44}\times 0.00632=0.00172g of carbon will be contained.

  • <u>For calculating the mass of hydrogen:</u>

In 18g of water, 2 g of hydrogen is contained.

So, in 0.00258 g of water, \frac{2}{18}\times 0.00258=0.000286g of hydrogen will be contained.

  • Mass of oxygen in the compound = (0.00278) - (0.00172 + 0.000286) = 0.000774 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.00172g}{12g/mole}=1.43\times 10^{-4}moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.000286g}{1g/mole}=2.86\times 10^{-4}moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.000774g}{16g/mole}=4.83\times 10^{-5}moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 4.83\times 10^{-5}mol

For Carbon = \frac{1.43\times 10^{-4}}{4.83\times 10^{-5}}=2.96\approx 3

For Hydrogen  = \frac{2.86\times 10^{-4}}{4.83\times 10^{-5}}=5.92\approx 6

For Oxygen  = \frac{4.83\times 10^{-5}}{4.83\times 10^{-5}}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 3 : 6 : 1

Hence, the empirical formula for the given compound is C_3H_{6}O_1=C_3H_6O

3 0
3 years ago
What is the speed of light of an orange light with a wavelength of 600nm and a frequency of 5.00x1014?
vovangra [49]

Answer:

3 × 10^8 m/s

Explanation:

The wavelength, can be calculated by using the following formula;

λ = v/f

Where;

λ = wavelength (m)

v = velocity/speed of light (m/s)

f = frequency (Hz)

According to the provided information in this question, λ = 600nm i.e. 600 × 10^-9m, f = 5.00 x 10^14 Hz

Hence, using λ = v/f

v = λ × f

v = 600 × 10^-9 × 5.00 x 10^14

v = 6 × 10^-7 × 5.00 x 10^14

v = 30 × 10^(-7 + 14)

v = 30 × 10^ (7)

v = 3 × 10^8 m/s

3 0
2 years ago
PLEASE HELP DUE TODAY 55 POINTS
Dvinal [7]

Answer : The final volume of gas will be, 26.3 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.974 atm

P_2 = final pressure of gas = 0.993 atm

V_1 = initial volume of gas = 27.5 mL

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 22.0^oC=273+22.0=295K

T_2 = final temperature of gas = 15.0^oC=273+15.0=288K

Now put all the given values in the above equation, we get:

\frac{0.974 atm\times 27.5 mL}{295K}=\frac{0.993 atm\times V_2}{288K}

V_2=26.3mL

Therefore, the final volume of gas will be, 26.3 mL

3 0
3 years ago
Read 2 more answers
Mitosis and Meiosis Lab Report
poizon [28]

Answer:

Mitosis and Meiosis Lab Report

Instructions: In the Mitosis and Meiosis lab, you investigated sexual and asexual reproduction as well as the processes of cellular division by mitosis and meiosis. Record your observations in the lab report below. You will submit your completed report.

________________________________________

Name and Title:  

Mitosis and Meiosis Lab Report.  

Objective(s):  

To learn and explore what mitosis and meiosis is and what they do.  

Hypothesis:

Record your predictions during the zoo tour section of the lab in the data chart.

Procedure:

First, go into the mitosis and meiosis cycles. Then look at what happens when a sex cell from a female tiger is combined with a sex cell from a male tiger. Then investigate what happens when two starfish reproduce asexually. Then write down the predictions about how each organism will replicate. Then, keep track on whether or not the forecast was right.

Data:  

Record your data from the zoo tour in the data chart below. Be sure to fill in the chart completely.

Zoo Organism Reproduction Prediction

(sexual, asexual, or both) Reproduction Result

(sexual, asexual, or both)

Elephant Sexual Sexual

Whiptail lizard Asexual Asexual

Parrot Sexual Sexual

Redwood tree  Both Both

Amoeba Asexual Asexual

Jellyfish Asexual Both

Conclusion:  

Your conclusion will include a summary of your lab results and an interpretation of the results. Please write in complete sentences.

1. List one-way mitosis and meiosis are the same and one way they are different.

Meiosis has 2 cell divisions, but mitosis has just one cell division. Since the parent cell develops diploid cells, meiosis I is the same as mitosis. The distinction between meiosis and mitosis is that after the whole process, meiosis produces genetically distinct haploid daughter cells, while mitosis produces genetically identical diploid daughter cells.

2. What is one advantage and one disadvantage of sexual reproduction?

The greatest benefit of sexual reproduction is that it aids in the development of offspring that are well suited to environmental environments due to genetic differentiation. As a result, the nation has a diverse range of descendants. The downside is that it needs two parents and takes longer than asexual reproduction.

3. What is one advantage and one disadvantage of asexual reproduction?

Asexual reproduction has the advantage of requiring only one parent, taking a short amount of time, and producing genetically identical offspring. The only drawback is that when there is a catastrophe, the mortality rate is poor due to the generation of genetically identical offspring.

4. Some living organisms are capable of both asexual and sexual reproduction. Explain how this can be an advantage.

To produce offspring, the organism may use either sexual or asexual reproduction. If it is difficult to find a mate, the living being will use asexual reproduction to produce offspring quickly. Sexual reproduction is possible because the individual requires genetically distinct offspring for survival.

Explanation:

Try to paraphrase evrything. I already paraphrased the procedure but i reccomend using the website "quillbot" to paraphrase evrything else so you dont get in trouble! If you have any qustions im here to answer ;)

6 0
3 years ago
Read 2 more answers
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