Answer:
R = mg
F = µsR
Fs= 0.4 × ( 88 × 10)
Fs = 772 N
Fk= µk R
Fs= 1.33 × 880 N
Net force = (772+(1.33×880))-240 N
Answer:
b
<u>to</u><u> </u><u>determine</u><u> </u><u>the</u><u> </u><u>frequency</u><u> </u><u>you</u><u> </u><u>must</u><u> </u><u>know</u><u> </u><u>oscillations</u><u> </u><u>and</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>time</u>
If time is specified, the distance may be estimated in constant acceleration using the formula: X=(at2)/2 if the beginning velocity is 0. (A automobile begins from a stop...) As a result, X=(6*10*10)/2=600/2 = 300 m.