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3 years ago

What are nasa's four great observatories and in what parts of the electromagnetic spectrum do they observe?

2 answers:

6 0

1) Hubble Space Telescope- Visible and near-ultraviolet
2) Compton Gamma Ray Observatory- Gamma Rays
3) Chandra X-ray Observatory- X-rays
4) Spitzer Space Telescope- infrared

LenaWriter [7]3 years ago

3 0

Answer:

HUbble space obsevatory

Explanation:

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Two positive charges of magnitude 20 micro C and 100 micro C are placed at a distance of 150cm. Calculate the force of repulsion

Luba_88 [7]

$first \: positive \: charge = q1 = 20$

$1micro \: = {1}^{ - 6}$

$1q = 20 \times 10 {}^{ - 6}$

$second \: charge = q2 = 100 \times 10 {}^{ - 6}$

$formula = f = \frac{k \times q1 × q2}{d {}^{2} }$

remember

$k = 9 \times {10}^{9}$

change distance 150cm to 1.5m

putting values

f = $\frac{9 \times 10 {}^{9} \times 20 \times 10 {}^{ - 6} \times 100 \times {10}^{ - 6} }{1.5 {}^{2} }$

<h2 /><h3>answer </h3><h3><u>8</u><u>N</u></h3>

4 0

3 years ago

A ray of light is traveling from water into a diamond. Upon hitting the diamond, a light ray bends toward the normal. With this

Flura [38]

As the light pass through different media, it experiences a refraction. This is a phenomenon where the speed and direction of light changes. If the ray of light moves towards the normal line, the angle is decreased. So, is the speed of that light.

6 0

4 years ago

Read 2 more answers

A superball and a clay ball are dropped from a height of 10cm above a tabletop. They have the same mass 0.05kg and the same size

Olenka [21]

Answer:4.08 N

Explanation:

Given data

superball dropped from a height of 10 cm

Mass of ball $\left ( m\right )$ =0.05kg

time of contact $\left ( t\right )$ =34.3 $\times 10^{-3}$ s

Now we know impulse = $Force\times time\ of\ contact$ =Change in momentum

$F_{average}\times t$ = $m\left ( v-(-v)\right )$

and velocity at the bottom is given by

v= $\sqrt{2gh}$

$F_{average}\times 34.3\times 10^{-3}$ = $0.05\left ( 1.4-(-1.4)\right )$

$F_{average}$ =4.081N

5 0

3 years ago

You drive a car for 2.0 h at 60 km/h, then for another 3.0 h at 85 km/h. What is your average velocity

Anon25 [30]

Answer:

Explanation:

Average velocity is found in the total displacement experienced in the trip divided by the total time it took to make this trip. If, for the first 2.0 hours, the car travels at 60 km/hr, then in 2.0 hours the car can travel 120 km; if it then travels for 3.0 at 85 km/hr, it can travel 255 km in the same direction. The total time this took was 5.0 hours. So doing the math and rounding correctly by following the rules for the adding and subtracting of sig fig's:

$v=\frac{120+255}{5.0}=\frac{380}{5.0}=76\frac{km}{hr}$