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3 years ago

How to breath??? pls explain

Physics

1 answer:

arsen [322]3 years ago

8 0

Answer:

Explanation:

Breathing consists of 2 processes :-

1) Inhaling ---> Taking the air in through nose.

2) Exhaling ---> Removing the air out through nose.

First we inhale & then we exhale. This complete process is known as breathing.

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An astronaut is in equilibrium when he is positioned 140 km from the center of asteroid C and 581 km from the center of asteroid

serg [7]

Answer:B

Explanation:

Given

Distance of astronaut From asteroid x is $r_x=140 km$

Distance of astronaut From asteroid Y is $r_y=581 km$

Suppose M,M_x,M_y be the masses of Astronaut , asteroid X and Y

If the astronaut is in equilibrium then net gravitational force on it is zero

$F_x=F_y$

$\frac{GMM_x}{r_x^2}=\frac{GMM_y}{r_y^2}$

cancel out the common terms we get

$\frac{M_x}{r_x^2}=\frac{M_y}{r_y^2}$

$\frac{M_x}{M_y}=(\frac{r_x}{r_y})^2$

$\frac{M_x}{M_y}=(\frac{140}{581})^2$

$\frac{M_x}{M_y}=0.05806\approx 0.0581$

8 0

3 years ago

A resistor, inductor, and capacitor are connected in series, each with effective (rms) voltage of 65 V, 140 V, and 80 V respecti

Morgarella [4.7K]

Answer:

The value of the effective (rms) voltage of the applied source in the circuit is 132 V

Explanation:

Given;

effective (rms) voltage of the resistor, $V_R$ = 65 V

effective (rms) voltage of the inductor, $V_L$ = 140 V

effective (rms) voltage of the capacitor, $V_C$ = 80 V

Determine the value of the effective (rms) voltage of the applied source in the circuit;

$V= \sqrt{V_R^2 + (V_L^2-V_C^2} )\\\\V= \sqrt{65^2 + (140^2-80^2} )\\\\V = \sqrt{4225+ 13200} \\\\V = \sqrt{17425} \\\\V = 132 \ V$

Therefore, the value of the effective (rms) voltage of the applied source in the circuit is 132 V.

6 0

4 years ago

You observe two stars over the course of a year (or more) and find that both stars have measurable parallax. (1 arc second is 1/

Ierofanga [76]

Answer:

Star X is much closer since it is at a distance 1 parsec from the Earth.

Explanation:

The angle due to the change in position of a nearby object against the background stars it is known as parallax.

The parallax angle can be used to find out the distance by means of triangulation. Making a triangle between the nearby star, the Sun and the Earth. This angle is gotten when the position of the object is measured in January and then in July according to the configuration of the Earth with respect to the Sun in those months.

The distance between the Earth and the Sun is 150000000 Km. That distance is also known as an astronomical unit (1AU).

The parallax angle can be defined in the following way:

$\tan{p} = \frac{1AU}{d}$

Where d is the distance to the star.

$p('') = \frac{1}{d}$ (1)

Equation (1) can be rewritten in terms of d:

$d(pc) = \frac{1}{p('')}$ (2)

Equation (2) represents the distance in a unit known as parsec (pc).

Case of Star X (p('') = 1):

Using equation 2 the distance of star X can be known:

$d(pc) = \frac{1}{1}$

$d(pc) = 1 pc$

So, star X is at 1 parsec from Earth.

Case of Star Y ( $p('') = \frac{1}{2}$ ):

$d(pc) = \frac{1}{(\frac{1}{2})}$

$d(pc) = 2 pc$

So, star Y is at 2 parsecs from the Earth.

Hence, star X is much closer.

Reminder:

Notice that in equation 2 the distance is inversely proportional to the parallax angle, so if the parallax angle decreases, the distance increases.

5 0

3 years ago

A particle travels along the curve from A to B in 5 s. It takes 8 s for it to go from B to C and then 10 s to go from C to A. De

Elza [17]

Answer:

5.1 m/s

Explanation:

The figure is missing: find it in attachment.

In order to find the average speed, we have to calculate the length of the total path, and divide it by the total time elapsed.

The curve from A to B is a quarter of a circle with a radius of r = 20 m, so its length is:

$AB=\frac{\pi r}{2}=\frac{\pi (20)}{2}=31.4 m$

The path BC is the hypothenuse of a right triangle with sides equal to 20 m and 30 m, so its length is

$BC=\sqrt{30^2+20^2}=36 m$

Finally, the length of the path AC is the sum of the side of 30 m and the radius of the curve, so

$AC=30 + 20 = 50 m$

So the total distance covered is

$d=AB+BC+AC=31.4+36+50=117.4 m$

The total time elapsed is

$t=5 s + 8 s + 10 s =23 s$

So, the average speed is

$v=\frac{d}{t}=\frac{117.4}{23}=5.1 m/s$

6 0

3 years ago

State the conservation laws

oee [108]

Answer:

conservation law os also called law of conservation it states that a certain physical property does not change in the course of time within a isolated physical system

7 0

3 years ago