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Scorpion4ik [409]
3 years ago
6

Convert 345 g to kg Determine the conversion factor and the answer (1,000 g = 1 kg)

Chemistry
1 answer:
Musya8 [376]3 years ago
6 0

Answer:

345000 grams

Explanation:

1000g = 1kg

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if you add 4.21 mL of solution from a buret into a flask that already contained 80.4 mL of solution, what is the total volume of
NNADVOKAT [17]

Answer:

84.6 mL

Explanation:

To get the total volume of soultion we must add the given volumes together.

4.21 mL + 80.4 mL = 84.6 mL

5 0
4 years ago
What is the daughter nucleus produced when zn63 undergoes electron capture? replace each question mark with the appropriate inte
GarryVolchara [31]

The daughter nucleus that is produced is ₂₉⁶³cu.

What is Electron capture?

The process of drawing an electron to the nucleus, where it combines with a proton to create a neutron and a neutrino particle, is known as electron capture.

The daughter nucleus is the nucleus that is made by the parent nucleus. The nucleus that remains after the decay is called the daughter nucleus.

Here is the chemical formula for the reaction that results in the electron capture of the zinc-63 nucleus:

_A^ZX + e^- =  _A^Z_-_1 Y + ye

_3_0^6^3Zn\; + e^- = _2_9^6^3Cu + ye

Thus, the daughter nucleus produced when zn63 undergoes electron capture is _2_9^6^3Cu.

To learn more about Electron capture, refer to the below link:

brainly.com/question/10964824

#SPJ4

4 0
2 years ago
What happens after we die? spirtually and physically
GREYUIT [131]
We will never come back
3 0
3 years ago
Read 2 more answers
The pH of a 0.78M solution of 4-pyridinecarboxylic acid HC6H4NO2is measured to be 2.53.Calculate the acid dissociation constant
nika2105 [10]

Answer : The value of acid dissociation constant is, 1.1\times 10^{-5}

Solution :  Given,

Concentration pyridinecarboxylic acid = 0.78 M

pH = 2.53

First we have to calculate the hydrogen ion concentration.

pH=-\log [H^+]

2.53=-\log [H^+]

[H^+]=2.95\times 106{-3}M

Now we have to calculate the acid dissociation constant.

The equilibrium reaction for dissociation of (weak acid) is,

                        HC_6H_4NO_2\rightleftharpoons C_6H_4NO_2^-+H^+

initially conc.         0.78                0             0

At eqm.               (0.78-x)              x             x  

The expression of acid dissociation constant for acid is:

k_a=\frac{[C_6H_4NO_2^-][H^+]}{[C_6H_4NO_2]}

As, [H^+]=[C_6H_4NO_2^-]=x

So,  x=2.95\times 106{-3}M

Now put all the given values in this formula ,we get:

k_a=\frac{(x)\times (x)}{(0.78-x)}

k_a=\frac{(2.95\times 106{-3})\times (2.95\times 106{-3})}{(0.78-2.95\times 106{-3})}

K_a=1.1\times 10^{-5}

Therefore, the value of acid dissociation constant is, 1.1\times 10^{-5}

7 0
4 years ago
Iron-59 is used in medicine to diagnose blood circulation disorders. The half life of iron-59 is 44.5 days. How much of a 2.000
kolezko [41]

Answer:

0.258 mg of iron remains.

Explanation:

To solve this problem we can use the formula

M₂ = M₀ * 0.5^{\frac{t}{44.5} }

Where M₂ is the mass remaining, M₀ is the initial mass, and t is time in days.

Using the data given by the problem:

M₂ = 2.000 mg * 0.5^{\frac{133.5}{44.5} }

M₂ = 0.258 mg

7 0
3 years ago
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