Water donates a proton in the forward reaction and H2C03 donates a proton in the reverse.

The answer on plato is c

**Answer:**

ΔT = 76.5 °C

**Explanation:**

**Given data:**

Amount of water = 100.0 g

Energy needed = 32000 J

Change in temperature = ?

**Solution,**

**Formula:
**

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Now we will put the values in formula.

Q = m.c. ΔT

ΔT = Q / m.c

ΔT = 32000 j/ 100.0 g × 4.184 j/g. °C

ΔT = 32000 j / 418.4 j /°C

ΔT = 76.5 °C

**Answer:**

30 psi

**Explanation:**

P₁V₁ = P₂V₂

(15psi) (2.6L) = P₂(1.30L)

Solve for P₂

(15psi) (2.6L)

------------------ = P₂ = 30 psi

(1.30L)

**Answer:**

The mass of 3.5 moles of Ca is 140 g to two significant figures.

**Explanation:**