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joja [24]
3 years ago
9

Here is the reaction of carbamic acid and ammonia to form an amide and water. There is a scheme of a reversible reaction where c

arbamic acid reacts with ammonia to give water and an unknown compound. Carbamic acid is H2NCOH with an oxygen atom attached to the carbon atom by a double bond. Ammonia is a nitrogen atom with three H atoms attached. Water is HOH. Draw the amide product of this reaction.
Chemistry
1 answer:
vladimir2022 [97]3 years ago
4 0

Answer:

See explanation

Explanation:

I have attempted to show the sequence of the reaction between carbamic acid and ammonia to form an amide and water and urea.

The reaction first involves the protonation of ammonia to give ammonium carbamate.

When ammonium carbamate is heated to 130-140 degrees, we obtain urea and water as the final products of the reaction

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When a aqueous solution of a certain acid is prepared, the acid is dissociated. Calculate the acid dissociation constant of the
stepan [7]
<h2>K_a = \dfrac{[H^{+}] [A^{-}]}{[HA]}</h2>

Explanation:

  • When an aqueous solution of a certain acid is prepared it is dissociated is as follows-

        {\displaystyle {\ce {HA  ⇄  {H^+}+{A^{-}}}  }}

Here HA is a protonic acid such as acetic acid, CH_3COOH

  • The double arrow signifies that it is an equilibrium process, which means the dissociation and recombination of the acid occur simultaneously.
  • The acid dissociation constant can be given by -

        K_a = \dfrac{[H^{+}] [A^{-}]}{[HA]}

  • The reaction is can also be represented by Bronsted and lowry -

         \\{\displaystyle {\ce {{HA}+ H_2O} ⇄  [H_3O^+] [A^-]

  • Then the dissociation constant will be

        K_a = \dfrac{[H_3O^{+}] [A^{-}]}{[HA]}

Here, K_a is the dissociation constant of an acid.

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How many molecules are there in 24 grams of FeF(3)?
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Answer:

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Explanation:

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