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Artemon [7]
3 years ago
15

Prisms separate light, such as that from the Sun, by wavelength

Physics
1 answer:
SVETLANKA909090 [29]3 years ago
6 0
Sorry I'm so late, but I just took this test and the answer is white (for people who didn't study well ;) )
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Do all substances radiate heat
a_sh-v [17]
I don't believe they do
6 0
3 years ago
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Please help! I especially need help with the second question but help with the first one would be most appreciated!
lara31 [8.8K]

Answer:

a) Team A will win.

b) The losing team will accelerate towards the middle line with 0.01 m/s^{2}

Explanation:

Given that Team-A pulls with a force , F_{1} = 50N

and Team-B pulls with a force , F_{1} = 45N

∵ F_{1} > F_{2}

The rope will move in the direction of force F_{1}.

∴ Team-A will win.

b) Considering both the teams as one system of total mass , m = 246+253 = 499 kg

Net force on the system , F = F_{1} - F_{2} = 50-45 = 5N

Applying Newtons first law to the system ,

F = ma , where 'a' is the acceleration of the system.

Since , both the teams are connected by the same rope , their acceleration would be the same.

∴ 5 = 499×a

∴ a = 0.01 m/s^{2}

4 0
4 years ago
What will happen to a negatively charged particle placed at rest between points that have electric potentials 0V and 9V? Explain
finlep [7]

Hey there!

a) The electric field is in direction of decreasing value of potential so the electric field here will points towards 0v from 9 v. But the charge on particle is negative so the force will be towards the 9v point. and so the charge will move towards the 9 V point.

b) Electric potential is a location-dependent quantity that expresses the amount of potential energy per unit of charge at a specified location while.the electric potential difference is the difference in electric potential (V) between the final and the initial location when work is done upon a charge to change its potential energy. Electric potential is always a relative quantity because no one can find out absolute potential at a point, so in reality only potential difference exists. We can assume potential at certain point (say at infinity it is zero) only then we are able to define potential at every point.

c) The knowlendge of electric potential helps us in finding the work done on the particle which is used in work energy theorem to find out the chanrge in kinetic energy and other stuff.

Hope this helps!

8 0
3 years ago
A complete description of simple harmonic motion must take into account several physical quantities and various mathematical rel
vazorg [7]

Answer:

Explanation:

x = 2 cos wt = 2 cos 10t ; w = 10

velocity = dx/dt = -2 x 10 sin 10 t.=- 20 sin 10t

t = .4

velocity = -20 sin 10 x .4 = -20 sin 4 = -20 x -0.7568 = 15.136 cm /s

w = √ k / m = 10 = √ k / .05

k = 15.136  N/m

8 0
3 years ago
Read 2 more answers
A white dwarf has a greater mass than either a red dwarf or a brown dwarf. Yet a white dwarf has a smaller radius than either a
Sauron [17]

Explanation:

Red dwarf and brown dwarf masses are less than a typical white dwarf mass measuring around 1.2 solar masses. But it's only a few kilometers of the radius. This is precisely because there is no force to overcome the contraction due to gravity. There is a constant  battle between the external force of fusion (who wants to expand the star) and inward pressure because of gravity (who wants to compact the star) of regular stars on the main sequence. There remains a balance between these two forces as long as the star remains on the celestial equator.

Red dwarfs are helped by the nuclear fusion force, but brown dwarfs were not large enough to cause the fusion of hydrogen, they are massive enough to generate sufficient energy in the core by fusing deuterium to sustain their volume.  However as soon as the star runs out of hydrogen to burn it weakens the force of the external fusion and gravity starts to compact the center of the star. The contraction heats up the core into more massive stars and helium fusion begins, rendering the star once again stable. However this helium fusion does not occur in stars with masses below 1.44Mo. Tightness persists for such stars until the star's gasses degenerate.

8 0
4 years ago
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