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Akimi4 [234]
3 years ago
11

A car is traveling at 20 meters/second and is brought to rest by applying brakes over a period of 4 seconds what is its average

acceleration over this time interval?
Physics
2 answers:
Fofino [41]3 years ago
7 0
Avg. acceleration = -5 m/s^2.
LuckyWell [14K]3 years ago
3 0

Answer:

Acceleration of the car is -5\ m/s^2

Explanation:

It is given that,

Initial speed of the car, u = 20 m/s

Finally, it brought to rest, v = 0

Time taken, t = 4 s

We need to find the average acceleration over this time interval. The acceleration of an object is given by following formula as :

a=\dfrac{v-u}{t}

a=\dfrac{-(20\ m/s)}{4\ s}          

a=-5\ m/s^2

So, the car is decelerating at 5\ m/s^2. Hence, this is the required solution.

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The moon revolves around earth at a fairly constant speed.Is the moon accelerating
inysia [295]
<span>If the moon changes direction, it's because it is orbiting around the earth, and the moon  keeps a constant speed. And when the moon turns, it accelerates due to velocity. So yes, the moon accelerates. </span>
7 0
3 years ago
Insect A moves 5.0 m/min and insect B moves
mezya [45]

Answer:

insect B by 12m

Explanation:

30min = 1800s (times by 60)

5m/min x 30min = 150m

9cm/s x 1800s = 16,200cm = 162m

162m - 150m = 12m

6 0
3 years ago
If a spring is stretched to twice the lengtj of its equilibrium position, by what factor does the energy stored in the spring ch
mylen [45]

Answer:

the energy increases 4 times

Explanation:

A spring has an elastic potential energy that is given by the expression

          K_e = ½ K (x-x₀)²

where x is the distance from the equilibrium point and k is the return constant

if the spring is stretched at  x-x₀ = 2x₀, the energy value

        K_e = ½ k (2x₀)²

        K_e = ½ k 4 x₀²

        K_e = 4 (½ k x₀²)

        \frac{K_e}{ \frac{1}{2} k x_o^2} = 4

therefore the energy increases 4 times

6 0
3 years ago
Calculate the frequency of the wave shown below.
jenyasd209 [6]

\color{skyblue}{ \underline{  \frak { \: option \: ( \: c \: )  =  2 \: hertz   ✓}}}

\:  \:

Given :

  • Wavelength ( λ ) = 2 m

\:  \:

  • Speed = 4 m/s

\:  \:

We, have to find frequency :

\:

  • \large \tt \: Frequency =  \frac{Speed}{Wavelength ( \: λ \: )}

\:  \:

  • \large \tt \: Frequency =  \frac{4}{2}

\:  \:

  • \large \tt \: Frequency = \cancel  \frac{4}{2}

\:  \:

  • \pink{ \boxed{\large \tt \: Frequency =2 \: Hertz ✓}}

\:  \:

Hope Helps!

5 0
2 years ago
Describe the position of the sun, moon, and earth during a new moon and a full moon.
Gennadij [26K]

Answer:

* he new moon phase when the position is       Sun - Moon - Earth,

* have of the Full Moon when the position is     Sun - Earth - Moon,

*All the phases of the moon are governed by the movement of the Moon around the Earth.

Explanation:

In the solar system, the planets revolve around the sun, which is much more massive, in the case of the Earth it is more massive than its satellite, therefore the Moon revolves around the Earth in a period of approximately 28 days.

It is said that the moon is in the new moon phase when the position is Sun - Moon - Earth, so the moon cannot be seen

It is in the phase of the Full Moon when the position is

                  Sun - Earth - Moon, in this case the moon can be observed by the light reflected from it.

All the phases of the moon are governed by the movement of the Moon around the Earth.

8 0
3 years ago
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