Answer:
The answer is 960 kg
Explanation:
Solution
Given that:
Assume the initial dye concentration as A₀
We write the expression for the dye concentration for one hour as follows:
ln (C₁) = ln (A₀) -kt
Here
C₁ = is the concentration at 1 hour
t =time
Now
Substitute 480 g for C₁ and 1 hour for t
ln (480) = ln (A₀) -k(1) ------- (1)
6.173786 = ln (A₀) -k
Now
We write the expression for the dye concentration for three hours as follows:
ln (C₃) = ln (A₀) -k
Here
C₃ = is the concentration at 3 hour
t =time
Thus
Substitute 480 g for C₃ and 3 hour for t
ln (120) = ln (A₀) -k(3) ------- (2)
4.787492 = ln (A₀) -3k
Solve for the equation 1 and 2
k =0.693
Now
Calculate the amount of blue present initially using the expression:
Substitute 0.693 for k in equation (2)
4.787492 = ln (A₀) -3 (0.693)
ln (A₀) =6.866492
A₀ =e^6.866492
= 960 kg
Therefore, the amount of the blue dye present from the beginning is 960 kg
Answer:
One gallon of paint can cover about 400 square feet of wall.
18 x 15 feet is 270 feet of space.
270/400 = .675 gallons for one coat on one wall
.675 x 4 = 2.7 gallons for one coat on all walls
2.7 gallons x 2 = 5.4 gallons of paint in all
Answer:
a) Thermal conductivity of skin: 
b) Temperature of interface: 
Heat flux through skin: 
Explanation:
a)
Where: 
is thermal conductivity of a material, 
is heat flux through a material, 
is the thickness of the material, 
is the temperature on the first side and 
is the temperature on the second side
b)
The heat flux between both surfaces is constant, assuming the temperature is maintained at each surface.
Answer:
B) voltage at the sending end of the feeder = 2483.66 v
Explanation:
attached below is the the equivalent circuits and the remaining solution for option A
B) voltage = 2400 v
I = 
= 20.83 A
calculate voltage at sending end ( Vs )
Vs = 2400 + 20.83 ∠ -cos^-1 (0.8) ( 0.75*2 + 0.5 + j 2 + j2 )
hence Vs = 2483.66 ∠ 0.961
therefore voltage at the sending end = 2483.66 v
