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a_sh-v [17]
3 years ago
8

Consider a 2D airfoil with a zero lift angle of attack of −4 degrees. The stall angle for this airfoil is 15 degrees, where the

maximum 2D lift coefficient is found to be 2.0. This airfoil is used in an aircraft with a non-elliptic wing of span 20m and planform area of 60 m2 . If ????1 = ????2 = 0.01, the weight of the plane is 105 Newton, density of air is 1 kg/m3 , find out the maximum landing speed that the plane can have
Engineering
1 answer:
zzz [600]3 years ago
4 0

Answer:

Explanation:

Recquired Data

lift coefficient = 2.0

Distance = 20m

Area = 60m²

Force = 105 N

Density = 1kg/m³

we are recquired to find Maximum panding speed

The lift coefficient CL is defined by

CL≡L/qs=L/1/2рμ²S = 2L/рμ²S

where L, is the lift force, S, is the relevant surface area and q, is the fluid dynamic pressure, in turn linked to the fluid density rho ,, and to the flow speed u,

substituting the figure respectively

2.0 = 2 X 105 / 1 X μ² X 60

μ² = 2L /CL X P X S

μ² = 2 X 150 / 2.0 X 1 X 60

μ² = 300 / 120

μ² = 2.5

μ =1.58ms⁻²

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Answer:

The correct option is;

A. proper protection

Explanation:

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3 years ago
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For a fluid with a Prandtl Number of 1000.0, the hydrodynamic layer is thinner than the thermal boundary layers. a) True b) Fals
kvv77 [185]

Answer:

(b)False

Explanation:

Given:

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  Where \nu is the molecular diffusivity of momentum

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 Prandtl number(Pr) can also be defined as

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In given question Pr>1 so  hydrodynamic boundary layer thickness will be greater than thermal boundary layer thickness.

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8 0
4 years ago
Explain any five applications of computer modeling in beams.
coldgirl [10]

Answer:

Explain any five applications of computer modeling in beams.

Explanation:

7 0
3 years ago
Tech A says that to read amperage, the meter must be hooked up in series in a circuit. Tech B says that to read amperage at a lo
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Answer:

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4 years ago
A specimen of some metal having a rectangular cross section 10.4 mm × 12.8 mm is pulled in tension with a force of 15900 N, whic
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Answer:

\sigma=0.00151

Explanation:

We apply Hooke's Law as follows :

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