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Stolb23 [73]
3 years ago
12

The answer to a chemistry question

Chemistry
1 answer:
Otrada [13]3 years ago
5 0
<span>4 C3H5(NO3)3 = 12 CO2 + 6 N2 + 10 H2O + O<span>2
That's the answer lovely~</span></span>
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An amino acid A, isolated from the acid-catalyzed hydrolysis of a peptide antibiotic, gave a positive ninhydrin test and had a s
Ede4ka [16]
The answer could be 23
7 0
3 years ago
List 2 things that about Velocity and Speed that are Different and two that are the same.
frozen [14]
Hey there!
Speed and velocity both:
1) Measure how fast something is moving
2) Both measured in miles per hour, meters/second, etc (rates)
However, there's a prime difference:
Different because:
1) Velocity is speed, but in a certain direction
2) Velocity is a vector
3) Velocity can be positive <em>or</em> negative, unlike speed.
I added another just in case you had a preference :)

Hope this helps!

8 0
3 years ago
How many grams of carbonic acid were produced by the 3.00 g sample of NaHCO
stellarik [79]
I think the given is 3 g sample of NaHCO3. then if it will be reacted with an acid, it will produce H2CO3.
 so the reaction NaHCO3 + HCl --> NaCl + H2CO3

mas of H2CO3 = 3 g NaHCO3 ( 1 mol NaHCO3 / 84 g ) ( 1 mol H2CO3 / 1 mol NaHCO3) ( 62.03 g / 1 mol )
mass of H2CO3 = 2.22 g H2CO3
7 0
3 years ago
How much heat is lost when 0.440 mol of steam condenses at 100 °C?
dusya [7]

Answer:

17,890 J

Explanation:

The amount of heat released by a gaseous substance when it condenses is given by the formula

Q=n\lambda_v

where

n is the number of moles of the substance

\lambda_v is the latent heat of vaporization

The formula can be applied if the substance is at its vaporization temperature.

In this problem, we have:

n = 0.440 mol is the number of moles of steam

\lambda_v=40,660 J/mol is the latent heat of vaporization of water

And the steam is already at 100C, so we can apply the formula:

Q=(0.440)(40660)=17,890 J

8 0
3 years ago
Phosphorus trichloride gas and chlorine gas react to form phosphorus pentachloride gas: PCl3(g)+Cl2(g)⇌PCl5(g). A 7.5-L gas vess
Tpy6a [65]

Answer:

The equilibrium constant in terms of concentration that is, K_c=3.6243\times 10^{3} .

Explanation:

PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

The relation of K_c\& K_p is given by:

K_p=K_c(RT)^{\Delta n_g}

K_p= Equilibrium constant in terms of partial pressure.=98.1

K_c= Equilibrium constant in terms of concentration  =?

T = temperature at which the equilibrium reaction is taking place.

R = universal gas constant

\Delta n_g = Difference between gaseous moles on product side and reactant side=n_{g,p}-n_{g.r}=1-2=-1

98.1=K_c(RT)^{-1}

98.1 =\frac{K_c}{RT}

K_c=98.1\times 0.0821 L atm/mol K\times 450 K=3,624.30=3.6243\times 10^{3}

The equilibrium constant in terms of concentration that is, K_c=3.6243\times 10^{3} .

5 0
3 years ago
Read 2 more answers
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