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Rzqust [24]
2 years ago
13

Complete the balancing of this equation ; which shows the reaction between iron and carbon :

Chemistry
1 answer:
rewona [7]2 years ago
5 0

The balanced equation is Fe_{2} O_{3}  + 3CO ---> 2Fe + 3CO_{2}

<u>Explanation</u>:

                        Fe_{2} O_{3}  + 3CO ---> 2Fe + 3CO_{2}

  • For solving this first of all you figure out the formula of iron(3)oxide so you look at the periodic table as you said valency of iron is 3 positive because metals are always positive and oxygen’s valency is 2 (negative because non-metal). You criss-cross both you take 2 from oxygen and put it under the iron and then 3 from iron under oxygen.
  • Valency is the number of electrons needed to be a noble gas.   Oxygen has 6 electrons in the outer shell and it needs 2 more to become noble gas.   The total number of electrons needed in every shell is 8 so to figure out valency you subtract the number of electrons in the outer shell from 8. Valency also shows how many electrons you need to share for bonding.
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DanielleElmas [232]

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Ca(OH)_{2} (aq) + CO_{2}(g) ----> CaCO_{3}(s) +H_{2}O(l)

2) When NH_{3} is released in a decomposition reaction we can identify by the strong pungent smell of the gas released.

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5 0
3 years ago
The compound adrenaline contains 56.7 % c, 6.56 % h, 28.37% o and 8.28 % n by mass. what is the empirical formula for adrenaline
-Dominant- [34]

Answer:- An empirical formula of adrenaline is C_8H_1_1O_3N .

Solution:- Convert given percentages to moles and then calculate the mol ratio to get the simplest whole number ratio of moles of atoms which is the empirical formula of the compound.

C=\frac{56.7}{12} = 4.725 mol

H=\frac{6.56}{1} = 6.56 mol

O=\frac{28.37}{16} = 1.773 mol

N=\frac{8.28}{14} = 0.591 mol

let's calculate the mol ratio now. To calculate the mole ratio, we divide the moles of each by moleso f N as it's the least one:

C=\frac{4.725}{0.591} = 8

H=\frac{6.56}{0.591} = 11

O=\frac{1.773}{0.591} = 3

N=\frac{0.591}{0.591} = 1

So, an empirical formula of adrenaline is C_8H_1_1O_3N .


3 0
3 years ago
Please help! Chemistry thermodynamics! 18 pts!
PSYCHO15rus [73]
200 kJ. 

For questions like these, it's generally the same number. See <span>First Law of Thermodynamics. </span>
3 0
3 years ago
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serg [7]
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3 years ago
What is the first step in balancing a redox reaction by the half-reaction method?
Oksi-84 [34.3K]
First step is to balance the amount of atoms on each side

So for example if my equation that I have to balance is : Br2 -> Br-

First thing I would have to do would be :
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Then I would have to balance the charges on both sides. So because there is a -2 charge on the right side I will have to add a -2 charge onto the right side as well. I would do this by :
Br2 + 2e- -> 2Br-

And now you can see the amount of atoms and the charges are balanced... So your overall reaction is now balanced too.
7 0
3 years ago
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