I need you to explain the question
Answer:
<h3><em>Calcium carbonate is heated strongly until it undergoes thermal decomposition to form calcium oxide and carbon dioxide. The calcium oxide (unslaked lime) is dissolved in water to form calcium hydroxide (limewater). Bubbling carbon dioxide through this forms a milky suspension of calcium carbonate.</em></h3>
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A and B should be correct
Aldehyde is a group of organic compounds with the general form of RCHO. Oxidation of aldehyde can lead to the formation of the carboxylic acids, with the general form of RCO₂H.
With this oxidation, the typical reagents promoting the oxidation are chromic acids, chromate salts, permanganate, etc.
Answer:
C 2sp³ + 2sp³ O
Explanation:
Carbon has an atomic number equal to <em>6</em>, so its electronic distribution is:
1s²2s²2p²
Oxygen has an atomic number equal to <em>8</em>, so its electronic distribution is:
1s²2s²2p⁴
In dimethyl ether, the bonds between carbon and hydrogen and carbon and oxygen are saturated, so there will be only sigma bonds. The sigma bonds occurs in hybrids orbitals, and pi bonds on normal orbitals. So, the carbons and the oxygen of that compound has hybridization
2sp³, because they need 4 hybrid orbitals.
So the bond C-O occurs between C 2sp³ + 2sp³ O
