A boy swings a ball on a string at constant speed in a circle that has a circumference equal to 6 m. What is the work done on th
e ball by the 10 N tension force in the string during one revolution of the ball
1 answer:
Answer:
0 J
Explanation:
From the diagram below; we would notice that the Force (F) = Tension (T)
Also the angle θ adjacent to the perpendicular line = 90 °
The Workdone W = F. d
W = Fd cos θ
W = Fd cos 90°
W = Fd (0)
W = 0 J
Hence the force is perpendicular to the direction of displacement and the net work done in a circular motion in one complete revolution is = 0
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Answer:
25 m/s in the opposite direction with the ship recoil velocity.
Explanation:
Assume the ship recoil velocity and velocity of the cannon ball aligns. By the law of momentum conservation, the momentum is conserved before and after the shooting. Before the shooting, the total momentum is 0 due to system is at rest. Therefore, the total momentum after the shooting must also be 0:
where are masses of the ship and ball respectively.
are the velocities of the ship and ball respectively, after the shooting.
So the cannon ball has a velocity of 25 m/s in the opposite direction with the ship recoil velocity.
Answer:
v = 1 m/s
Explanation:
from the principle of conservation of momentum, we have following relation
initial momentum = final momentum
where
m1 = 1.14 kg
v1 = 2.0 m/s
m2 = 1.14 kg
v2 = 0 m/s
putting all value in the above equation
v = 1 m/s