Two runners are competing in track meet. Samantha runs with a speed of 10 m/s and completes her race in 10 seconds. Jordin takes
2 answers:
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The average force on the squid during the ejection of 0.60 kg of water at a velocity of 15.0 m/s in 0.15 seconds is 60 N.
We can calculate the average force with the average acceleration as follows:
(1)
Where:
- m: is the mass of water = 0.60 kg
: is the average acceleration
The <em>average acceleration</em> is given by the change of velocity in an interval of time
(2)
Where:
: is the initial velocity = 0 (the squid is at rest)
: is the final velocity = 15.0 m/s
: is the initial time = 0
: is the final time = 0.15 s
Now we can find the <em>average force</em> after entering equation (2) into (1)
Therefore, the average force on the squid during the propulsion is 60 N.
Find more about average force here:
I hope it helps you!
Answer:
The value of capillary rise in the tube = 0.0363 cm
Explanation:
Diameter of the glass tube = 0.03 meter
Contact angle = 22 degree
We know that the capillary rise (h) in the tube is given by the formula =
h = (2 α cos β) / (d g R )
⇒ d = density of gasoline = 749 kg /
β = 22 degree
R = radius of the tube = 0.015 m
α = surface tension of gasoline = 0.0216 N / m
cos 22 = 0.927
Put all the values in the above formula we get
⇒ h = (2 × 0.0216 × 0.927) / (749 × 9.81 × 0.015)
⇒ h = 0.0363 cm
This is the value of capillary rise in the tube.