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aleksandr82 [10.1K]
3 years ago
7

Two runners are competing in track meet. Samantha runs with a speed of 10 m/s and completes her race in 10 seconds. Jordin takes

15 seconds to finish her race, running with a speed of 8 m/s. Which statement best describes the difference in the distance each runner ran?
A. Jordin's distance was longer by 10 meters.
B. Jordin's distance was longer by 20 meters.
C. Samantha's distance was longer by 2 meters.
D. Samantha's distance was longer by 10 meters.
Physics
2 answers:
Mashutka [201]3 years ago
6 0
The answer for this question is B.
Nostrana [21]3 years ago
3 0

Answer:

B. Jordin's distance was longer by 20 meters.

Explanation:

The distance Samantha runs = Samantha's speed ×  Samantha's time = 10 m/s × 10 s = 100 m

The distance Jordin runs = Jordin's speed × Jordin's time = 8 m/s × 15 s = 120 m.

The difference in the distance run = (120 - 100) m = 20 m.

So, Jordin's distance is 20 m more than that of Samantha.

So, Jordin's distance was longer by 20 meters is the answer.

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The wavelength of 10^15-Hz light is:
Vanyuwa [196]

Answer:

D.300nm

Explanation:

Wavelength = Speed of light / Frequency of light.....

where the speed of light is...(3 × 10^8)

Wavelength = (3 × 10^8)/(1 × 10^15)

Wavelength = 3 × 10^-7

;Wavelength = 300 × 10^-9

Hence its....300 nm

5 0
3 years ago
A 1000-kg car is driving toward the north along a straight horizontal road at a speed of 20.0 m/s. The driver applies the brakes
Nitella [24]

Answer:

The value of F= - 830 N

Since the force is negative, it implies direction of the force applied was due south.

Explanation:

Given data:

Mass = 1000-kg

Distance, d = 240 m

Initial velocity, v1 = 20.0 m/s

Final velocity, v2 = 0 (since the car came to rest after brake was applied)

v2²= v1² + 2ad (using one of the equation of motion)

0=  20² + (2 x a x  240)

0= 400 + 480 a

a = - 400/480

a = - 0.83 m/s²

Then, imputing the value of a into

F = ma

F = 1000 kg x ( - 0.83 m/s²)

F= - 830 N

The car was driving toward the north, and since the force is negative, it implies direction of the force applied was due south.

3 0
3 years ago
Two protons move at speed v, one along the x axis and one along the y axis. What is the relative speed of the two protons? Evalu
forsale [732]

Answer:

0.85 c

Explanation:

When the two travel at right angles to each other , their relative velocity is given by the hypotenuse formed by the x and y direction velocities.

Relative velocity of the two protons is  given as

\sqrt{v^{2}+v^{2}} = (\sqrt{2} ) v

If v = 3/5 c , then the relative speed = \sqrt{2} (3/5c) =0.85 c

8 0
3 years ago
Greg and Tabitha are jogging together. At time t = 0, they are both traveling at a speed of 4 m/s, but Greg is 8 m ahead of Tabi
Ray Of Light [21]

Answer:

The answer to question is below

Explanation:

Data

t1 = 0

vo = 4 m/s

a)

      d = vot + \frac{1}{2} at^{2}

      d = 4t + \frac{1}{2} (1)t^{2} + 8

      d = 8 + 4t + \frac{t^{2} }{2}

b)

      d = 4t + \frac{1}{2} (1.5)t^{2}

      d = 4t + 0.75t^{2}

c)    

       8 + 4t + \frac{t^{2} }{2}  =  4t + 0.75t^{2}

       4t + \frac{1}{2} t^{2} + 8 = 4t + \frac{1}{2} (1.5)t^{2} \\

       0.75t^{2} - 0.5t^{2}  = 8

       0.25t^{2} = 8

                      t² = 32

                      t = 5.66 s

d)

      d = 4(5.66) + 0.75(5.66)²

      d = 22.64 + 24.02

      d = 46.67 m

8 0
3 years ago
You are playing baseball and hit a single, running to first base. Your distance and displacement are
Harrizon [31]

Answer:

C. Distance 90 feet Displacement 0 feet

8 0
2 years ago
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