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3 years ago

A is the area of a chromosome pair that attaches to a fiber stretching

Physics

1 answer:

chubhunter [2.5K]3 years ago

5 0

The chromosome pair that attaches to fiber stretching is called Centrioles

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block is attached to an oscillating spring. The function below shows its position (cm) vs. time (s). What is the angular frequen

faltersainse [42]

Answer:

Angular frequency is 20 rad/s.

Explanation:

Given that,

A block is attached to an oscillating spring. The function below shows its position (cm) vs. time (s) is given by :

$x(t)=1.5\cos(20\ t)$ .....(1)

The general equation of oscillating particle is given by :

$x(t)=A\cos(\omega t)$ .......(2)

Compare equation (1) and (2) we get :

$\omega=20\ rad/s$

So, the angular frequency of the oscillation is 20 rad/s.

7 0

3 years ago

Find the velocity (in m/s) of a proton that has a momentum of 4.96 X 10^-19 kg.m/s.

kramer

Answer:

The velocity of the proton is $2.965*10^{8} \frac{m}{s}$

Explanation:

The momentum of a particle is defined as the product of its mass by its velocity and we can calculate it using the following formula:

p=m*v Equation (1)

Where:

p: Is the momentum in kg*m/s

m: Is mass of the particle in kg

v: Is the velocity of the particle in m/s

Data known:

m= 1,6726 × 10^–27 kg : mass of the proton

p= 4.96 X 10^-19 kg.m/s.

We replace this data in the Equation (1):

$4,96*10^{-19} =1.6726*10^{-27} *v$ $v=\frac{4.9*10^{-19} }{1.6726*10^{-27} }$

$v=(\frac{4.96}{1.6726} )*(10^{27-19} )$

$v=2,965*10^{8} m/s$

Answer: The velocity of the proton is $2.965*10^{8} \frac{m}{s}$

3 0

3 years ago

If a refrigerator is a heat pump that follows the first law of thermodynamics, how much heat was removed from food inside of the

vodomira [7]

The blank would be 286 Joules

6 0

3 years ago

An Aeolian harp (named after Aeolus, the Greek god of the wind) consists of several strings fixed to a frame or a sounding box.

Mashcka [7]

Answer:

0.434 m

Explanation:

We are given that

Mass per unit length= $\mu=\frac{m}{l}=2.4 g/m=2.4\times 10^{-3} kg/m$

1 kg=1000 g

Tension=350 N

Fundamental frequency=f=440 Hz

We have to find the length you should make it.

We know that

$l=\frac{1}{2f}\sqrt{\frac{T}{\mu}}$

Using the formula

$l=\frac{1}{2\times 440}\times\sqrt{\frac{350}{2.4\times 10^{-3}}}$

l=0.434 m

Hence, you should make it 0.434 m long.

5 0

3 years ago

A 6450kg gorilla slides down the side of a 20m tall mountain at 47degrees. If the coefficient of kinetic friction is 0.23, what

blondinia [14]

Answer:

I have no idea but next time don't put so many points.

5 0

3 years ago