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3 years ago

For metalloids on the periodic table, how do the group number and the period number relate?

Physics

2 answers:

kotegsom [21]3 years ago

8 0

Answer : The correct option is, (1) The lower the group number, the lower the period numbers, so the metalloids are found in a diagonal moving down from left to right.

Explanation :

Metalloids : These are the elements which shows both the property of metals and non-metals that means the metalloids are present in between the metals and non- metals elements.

Boron, silicon, germanium, arsenic, antimony, tellurium and polonium are the metalloids.

In the periodic table, the metals are present on the left side, non-metals are present on the right side and the metalloids are present between the metals and non-metals.

The relation between the group number and the period number is :

The lower the group number, the lower the period numbers. So, the metalloids are found in a diagonal moving down from left to right.

Hence, the correct option is, (1)

The periodic table is also shown below.

lapo4ka [179]3 years ago

3 0

Im guessing it's (a) since the numbers go in chronological order and you read the periodic table left to right

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3 years ago

The drawing shows 6 point charges arranged in a rectangle. The value of q is 2.83 uC and the distance d is 0.123 m. Find the tot

vova2212 [387]

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2 years ago

which component of the Star Wars movies is possible according to our current understanding of physics?

Lena [83]

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4 years ago

(a) What is the current involved when a truck battery sets in motion 720 C of charge in 4.00 s while starting an engine? (b) How

OLEGan [10]

Answer:

(a) Current flowing through truck battery is 180 A

(b) Time taken in calculator is 333.33 s

Explanation:

(a) Given:

The charge on the truck battery,q = 720 C

Time, t = 4.00 s

Consider I be the current flowing through truck battery.

The relation between current, charge and time is:

I = q/t

Substitute the suitable values in the above equation.

$I=\frac{720}{4}$

I = 180 A

(b) Given:

The charge on the calculator,q = 7.00 C

The current flowing through calculator, I = 0.3 mA = 0.3 x 10⁻³ A

Consider t be the time.

The relation between current, charge and time is:

t = q/I

Substitute the suitable values in the above equation.

$t=\frac{1}{0.3\times10^{-3} }$

I = 333.33 s

8 0

3 years ago

A metallic wire has a diameter of 4.12mm. when the current in the wire is 8.00a, the drift velocity is 5.40×10−5m/s.

Darina [25.2K]

R = 2.06 mm = 2.06 x 10^(-3) m
Q = 1.6 x 10^(-19) C
v = 2.5 x 10^(-5) m/s
I = 8 A = 8 C/s
A = r² π = ( 2.06 x 10^(-3) ) ² x 3.14 = 13.325 x 10^(-6 ) m² =
= 1.3325 x 10^(-5) m²
I = n Q v A
n = I / (Q v A)
n = 8 C/s / ( 1.6 x 10 ^(-19) * 5.4 x 10^(-5) * 1.3325 x 10^(-5) ) =
= 0.694 x 10^(29) m^(-3)
n = 6.94 x 10^(28) m^(-3)

8 0

3 years ago

Read 2 more answers