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raketka [301]
3 years ago
11

A. Write two or three sentences to describe the conductivity of an insulator. Explain its conductivity in terms of the electrons

in it.
b. What is resistance? How does the resistance of a long wire compare with the resistance of a short wire? How does the resistance of a thick wire that has a large cross sectional area compare with the resistance of a thin wire?

c. What is the power of a lightbulb that has a current of 1.46 A at 120. V?
Physics
2 answers:
ololo11 [35]3 years ago
8 0

a) Conductivity originates from the word "conduct" and is being used when talking about how good (high conductivity) or how bad (low conductivity) materials allow charge carriers (electrons in metals) pass through the material. Insulator must isolate things, i.e. it must not have free electrons or electrons with weak ties that can make current.

b) Resistance lessens currents. Resistance is like a tube: water passes through short and wide tube easily and the current hardly passes through a long and thin tube.

c) P=IV=1.46*120=175.2 W.  

aliya0001 [1]3 years ago
3 0

PART A)

Conductivity of insulator is very small as there is no free electrons to conduct the current trough that medium

So here number of conduction electrons are very less in insulators

PART B)

Resistance is the property of a conducting medium which will oppose the flow of current trough it

Resistance of wire directly depends on its length so resistance of long wire will be more than the resistance of short wire

Resistance inversely depends on the area so if a wire has more crossectional area then its resistance must be small

PART C)

power of light bulb is defined as rate of electrical energy

it is given by formula

P = i V

here we know that

i = 1.46 A

V = 120 volts

so power is given as

P = 1.46 \times 120

P = 175.2 Watt

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aliya0001 [1]

We know that the change in momentum is equals to the product of force and time that is impulse (  F \times t). Therefore, we need to determine the value of that the water is in air by using the second equation of motion,

s=ut+\frac{1}{2} gt^2

Here, u is initial velocity which is zero.

s= \frac{1}{2} gt^2 \\\\ t = \sqrt{\frac{2s}{g} }.

Thus, impulse

= F \times \sqrt{\frac{2s}{g} }

From Newton`s second law,

F =mg

Therefore, impulse

= mg \times \sqrt{\frac{2s}{g} } = m \sqrt{2gs}

Given,  m = 7.3 kg and s = 2.0 m

Substituting these values, we get

Change in momentum = impulse  

= 7.3 \ kg \sqrt{2 \times 9.8 \ m/s^2 \times 2.0 \ m } = 45 .7 \ Ns.

8 0
3 years ago
Select the correct answer.
skelet666 [1.2K]

Answer:

B is the best answer for the question

6 0
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Read 2 more answers
1. While John is traveling along an interstate highway, he notices a 160-mile marker as he passes through town. Later John passe
pogonyaev

Number of miles that marker shows when passes through town= 160 miles.

Number of miles that marker shows currently to John = 115 miles.

We need to find the distance between town and John's current location.

For the problem, we can clearly see that Town is at 160 miles away but when John passes the marker shows 115 miles.

So, it's just the difference between 160 miles and 115 miles.

In order to find that difference, we need to subtract those two numbers.

160miles - 115miles = 45 miles.

So, we could say the distance between town and John's current location is 45 miles.

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Answer:

C). Take your foot off the gas pedal. Then brake lightly until you are moving at low speed.                    

Explanation:

While driving on roads of rural areas, if our right wheel moves off the pavement, we should always hold the steering wheel firmly and then take our foot off the gas pedal, then apply brake lightly until we are moving at a low speed.

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