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aivan3 [116]
3 years ago
13

Where would you find the element with least mass?

Chemistry
1 answer:
dexar [7]3 years ago
8 0
C. The lowest mass will be the element in period 1, group 1 (this element is hydrogen)

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What impact did the Spanish have on the region of South America?
vichka [17]

Answer:

The Spaniards practically went to war with the native Americans in South America, such as the Inca. They also brought diseases to South America. Diseases like smallpox.

Explanation:

Then after effectively killing off most of the native American population the Spanish continued to use South America for resources and they enslaved most of what was left of the non-Spanish and mixed populations. Francisco Pizarro took a page from Cortes' book, capturing Atahualpa, Emperor of the Inca, in 1532 and Cortes was the conquistador who defeated the Aztec Empire in what is now modern day Mexico or Central America.

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2 years ago
The orderly geometric arrangement of atoms is called a crystalline solid. <br> a. True<br> b. False
Crank
a.True.

The ordely geometric arrangement of atmos is called a crystalline solid.
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3 years ago
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The experimental apparatus represented above is used to demonstrate the rates at which gases diffuse. When the cotton balls are
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The correct answer is —-C
5 0
3 years ago
When 61.6 g of alanine (C3H7NO2) are dissolved in 1150. g of a certain mystery liquid X, the freezing point of the solution is 2
MrRissso [65]

Answer:

Explanation:

From the given information:

TO start with the molarity of the solution:

= \dfrac{61.6 \ g \times \dfrac{1 \ mol \ C_3H_7 NO_3}{89.1 \ g} }{1150 \ g \times \dfrac{1 \ kg}{1000 \g }}

= 0.601 mol/kg

= 0.601 m

At the freezing point, the depression of the solution is \Delta \ T_f = T_{solvent}- T_{solution}

\Delta \ T_f = 2.9 ^0 \ C

Using the depression in freezing point, the molar depression constant of the solvent K_f = \dfrac{\Delta T_f}{m}

K_f = \dfrac{2.9 ^0 \ C}{0.601 \ m}

K_f = 4.82 ^0 C / m}

The freezing point of the solution \Delta T_f = T_{solvent} - T_{solution}

\Delta T_f = 7.3^ 0 \ C

The molality of the solution is:

= \dfrac{61.6 \ g \times \dfrac{1 \ mol \ NH_4Cl}{53.5 \ g} }{1150 \ g \times \dfrac{1 \ kg}{1000 \g }}

Molar depression constant of solvent X, K_f = 4.82 ^0 \ C/m

Hence, using the elevation in boiling point;

the Vant'Hoff factor i = \dfrac{\Delta T_f}{k_f \times m}

i = \dfrac{7.3 \ ^0 \ C}{4.82 ^0 \ C/m \times 1.00 \ m}

\mathbf {i = 1.51 }

3 0
3 years ago
The boiling point of bromine is 59 °C. Which of the following best predicts the boiling point of iodine monochloride, a polar co
soldier1979 [14.2K]

Answer:

Higher than 59 °C because dipole-dipole interactions in iodine monochloride are stronger than dispersion forces in bromine.

Explanation:

I just took the test and i got it right

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