Answer:
655128 ohm
Explanation:
C = Capacitance of the capacitor = 7.8 x 10⁻⁶ F
V₀ = Voltage of the battery = 9 Volts
V = Potential difference across the battery after time "t" = 4.20 Volts
t = time interval = 3.21 sec
T = Time constant
R = resistance
Potential difference across the battery after time "t" is given as
T = 5.11 sec
Time constant is given as
T = RC
5.11 = (7.8 x 10⁻⁶) R
R = 655128 ohm
Answer:
Explanation:
distance between two slit d = 
d = 18.15 x 10⁻⁷ m
Let wave length of light λ
formula for position of first pair of bright spot
Tanθ = λ / d , λ is wave length of light and d is distance between two slit .
Tan 15.4 = 
λ = Tan 15.4 x 18.15 x 10⁻⁷
=5 x 10⁻⁷ m
If θ be the position of next bright spot
Tanθ = 2 λ / d
= 
=
θ = 28.4 degree .
Newtons law of the inversion gravitation state that every object in the universe attracts ever other object.
Answer:209.98 kJ
Explanation:
mass of water 
Initial Temperature of Water 
Final Temperature of water 
specific heat of ice 
Latent heat 
specific heat of water 
Heat require to convert water at
to 

Heat require to convert water at
to ice at 

heat require to convert ice at 

Total heat 

Answer:=14,160 kJ
Explanation: Let m1 and m2 be the initial and final amounts of mass within the tank, respectively. The steam properties are listed in the table below
Specific Internal SpecificTemp Pressure Volume Energy Enthalpy Quality Phase
C MPa m^3/kg kJ/kg kJ/kg
1 260 4.689 0.02993 2158 2298 0.7 Liquid Vapor Mixture
2 260 4.689 0.0422 2599 2797 1 Saturated Vapor
The mass initially contained in the tank is m1 = V/v1
m1 =0.85 m^3 /0.02993 m^3 /kg
= 28.4 kg
The mass finally contained in the tank is
m2 =V2/v
= 0.85 m^3 /0.0422 m^3 /kg
= 20.14 kg
The heat transfer is then
Qcv = m2u2 − m1u1 − he(m2 − m1)
Qcv = (20.14)(2599) − (28.4)(2158) − (2797)(20.14 − 28.4) = 14,160 kJ