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Rasek [7]
3 years ago
5

There are 3.78 liters in one gallon, therefore 3.78L = 1 Gallon. If I need 58 half-gallon containers for my boat, determine the

buoyant force that would be created.
Physics
1 answer:
Digiron [165]3 years ago
8 0

Answer:

F(b) =2142.106N

Explanation:

Given the following data

Volume is 3.78L which is 1 gallon

Therefore, 58gallons = 3.78×58 = 219.24L

Buoyant force F(b) = V(s) × d × g

Where V(s) = submerged volume = 219.24L = 0.21924m³

d = density of water = 997kg/m³

g = acceleration due to gravity = 9.8m/s²

Therefore F(b) = 0.21924m³× 997kg/m×9.8m/s²

F(b) =2142.106N

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Entific findings are useful
Kaylis [27]

That's true.  The give-away is "observation ... in the real world".  That's what "field reports" are.

The part I'm not so sure about is those "entific findings".

4 0
2 years ago
Light of a given wavelength is used to illuminate the surfacce of a metal, however, no photoelectrons are emitted. In order to c
Jlenok [28]

Answer:

B. use light of a shorter wavelength.

Explanation:

We know that

E= \frac{hc}{\lambda}

h= plank's constant

c= speed of light

λ= wavelength of the incident light

so, in order to have sufficient energy for for the emission of electron, the incident's radiation must have λ small enough.

B. use light of a shorter wavelength.

6 0
2 years ago
How long does it take an automobile traveling 66.7 km/h to become even with a car that is traveling in another lane at 52.7 km/h
tresset_1 [31]

Answer:

The  time taken is  t =  32.5 \  s

Explanation:

From the question we are told that

   The  speed  of  first car is  v_1  =  66.7 \ km/h  =  18.3 \  m/s

    The  speed  of  second car is v_2  =  52.7 \ km/h  =  14.64 \  m/s

   The  initial distance of separation is  d =  119 \ m

The distance covered by first car is mathematically represented as

     d_t =  d_i  +  d_f

Here  d_i is the initial distance which is  0 m/s

  and  d_f  is the final distance covered which is  evaluated as d_f  =  v_1 * t

So

     d_t =  0 \  m/s  +  (v_1 * t )

     d_t =  0 \  m/s  +  (18.3 * t )

The distance covered by second  car is mathematically represented as

     d_t =  d_i  +  d_f

Here  d_i is the initial distance which is  119 m

  and  d_f  is the final distance covered which is  evaluated as d_f  =  v_2* t

       d_t =  119  + 14.64 *  t

Given that the two car are now in the same position we have that

    119  + 14.64 *  t  =   0   +  (18.3 * t )

   t =  32.5 \  s

6 0
3 years ago
All biomes don’t have the same level of biodiversity. What seems to be the optimal conditions for high biodiversity?
irinina [24]

Answer:

See the answer below

Explanation:

The optimal conditions for high biodiversity seem to be a <u>warm temperature</u> and <u>wet climates</u>.

<em>The tropical areas of the world have the highest biodiversity and are characterized by an average annual temperature of above 18 </em>^oC<em> and annual precipitation of 262 cm. The areas are referred to as the world's biodiversity hotspots. </em>

Consequently, it follows logically that the optimal conditions for high biodiversity would be a warm temperature of above 18 ^oC and wet environment with annual precipitation of not less than 262 cm.

The variation in temperature and precipitation across biomes can thus be said to be responsible for the variation in the level of biodiversity in them.

6 0
3 years ago
What is the longest wavelength of light that will emit electrons from a metal whose work function is 3.70 eV
SSSSS [86.1K]

Answer:

h f = Wf + K

where the total energy available is h f, Wf is the work function or the work needed to remove the electron and K is the kinetic energy of the removed electron

If K = zero then hf = Wf

Wf = h f = h c / λ    or

λ = h c / Wf = 6.63E-34 * 3.0E8 / (3.7 * 1.6E-19)

λ = 6.63 * 3 / (3.7 * 1.6) E-7 = 3.36E-7

This would be 3360 angstroms or 336 millimicrons

Visible light = 400-700 millimicrons

6 0
1 year ago
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