That's true. The give-away is "observation ... in the real world". That's what "field reports" are.
The part I'm not so sure about is those "entific findings".
Answer:
B. use light of a shorter wavelength.
Explanation:
We know that

h= plank's constant
c= speed of light
λ= wavelength of the incident light
so, in order to have sufficient energy for for the emission of electron, the incident's radiation must have λ small enough.
B. use light of a shorter wavelength.
Answer:
The time taken is 
Explanation:
From the question we are told that
The speed of first car is 
The speed of second car is 
The initial distance of separation is 
The distance covered by first car is mathematically represented as

Here
is the initial distance which is 0 m/s
and
is the final distance covered which is evaluated as
So


The distance covered by second car is mathematically represented as

Here
is the initial distance which is 119 m
and
is the final distance covered which is evaluated as

Given that the two car are now in the same position we have that


Answer:
See the answer below
Explanation:
The optimal conditions for high biodiversity seem to be a <u>warm temperature</u> and <u>wet climates</u>.
<em>The tropical areas of the world have the highest biodiversity and are characterized by an average annual temperature of above 18 </em>
<em> and annual precipitation of 262 cm. The areas are referred to as the world's biodiversity hotspots. </em>
Consequently, it follows logically that the optimal conditions for high biodiversity would be a warm temperature of above 18
and wet environment with annual precipitation of not less than 262 cm.
The variation in temperature and precipitation across biomes can thus be said to be responsible for the variation in the level of biodiversity in them.
Answer:
h f = Wf + K
where the total energy available is h f, Wf is the work function or the work needed to remove the electron and K is the kinetic energy of the removed electron
If K = zero then hf = Wf
Wf = h f = h c / λ or
λ = h c / Wf = 6.63E-34 * 3.0E8 / (3.7 * 1.6E-19)
λ = 6.63 * 3 / (3.7 * 1.6) E-7 = 3.36E-7
This would be 3360 angstroms or 336 millimicrons
Visible light = 400-700 millimicrons