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Marizza181 [45]

3 years ago

10

What is an electron configuration?

1 answer:

Ulleksa [173]3 years ago

4 0

In atomic physics and quantum chemistry, the electron configuration is the distribution of electrons of an atom or molecule (or other physical structure) in atomic or molecular orbitals. For example, the electron configuration of the neon atom is 1s² 2s² 2p⁶, using the notation explained below.

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Silicon has four electrons in its outer energy level. What type of bond is silicon mostly likely to form with other elements? Ex

RideAnS [48]

Since it has 4 electrons, it needs only 4 more to be stable. Therefore, it would share electrons, which is a covalent bond.

Answer: Covalent bond

3 0

3 years ago

What is the smallest unit of an element called

steposvetlana [31]

The smallest unit of an element is called an Atom. An atom consists of protons, neutrons, and electrons.

8 0

4 years ago

Read 2 more answers

According to the periodic table, which two elements are in the same row? A. copper and gold B. sodium and sulfur C. lithium and

Korolek [52]

I think the answer is B. Correct me if i'm wrong :)

4 0

3 years ago

you have to prepare a ph 5.03 buffer, and you have the following 0.10m solutions available: hcooh, hcoona, ch3cooh, ch3coona, hc

TiliK225 [7]

Solution :

The buffer is the one that contains weak acid (the $\text{pK}_a$ is nearly equal to the required pH) and the salt of its conjugate base.

The $\text{pK}_a$ values of the given weak acids are as follows :

HCOOH : $\text{pK}_a$ = 3.744

$CH_3COOH : pK_a = 4.756$

HCN : $\text{pK}_a$ = 9.21

Since the required pH is 5.03, the suitable buffer is the mixture of the acetic acid and the salt of its conjugate base.

Let suppose the volumes of $CH_3COOH$ and $CH_3COONa$ are x and y mL respectively.

So the total volume of the buffer is 1000 mL.

∴ x+ y = 1000 ................(1)

Writing the Henderson-Hasselbalch equation for the given buffer solution :

$pH = pK_a + \log \ \frac{[CH_3COONa]}{[CH_3COOH]}$ .............(2)

$5.03 = 4.756 + \log \ \frac{\left(\frac{y \ mL \times 0.10 \ M}{(x+y) \ mL}\right)}{\left(\frac{x \ mL \times 0.10 \ M}{(x+y) \ mL}\right)}$

$5.03 = 4.756+ \log \frac{y}{x}$

$\frac{y}{x}=10^{5.03-4.756}$

y = 1.9 x

Substituting the values of y in equation (1), we get

x + 1.9 x = 1000

x = 345

Putting the value of x in (1), we get

345 + y = 1000

y = 655

Therefore the volume of $CH_3COOH$ is 345 mL and the volume of $CH_3COONa$ is 655 mL.

5 0

3 years ago

Draw the Lewis structure (including all lone pair electrons and any formal charges) for one of the four possible isomers of C3H9

Over [174]

Answer:

As shown in the attachment

Explanation:

The four possible isomers are as shown in the attachment.

3 0

3 years ago