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Tomtit [17]
3 years ago
6

A double carbon-carbon bond is found in a molecule of

Chemistry
1 answer:
ASHA 777 [7]3 years ago
3 0
The answer is (2) pentene. The family of compounds called "alkenes" (with the characteristic "-ene" suffix) is characterized by a double bond in the carbon backbone.
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If you have 200 grams of a radioactive sample, how many grams would be left after three half-lives?
Mumz [18]
Well, after 1 half life, depending on whatever the amount is, 50% of the original content and or remaining content will undergo decay, as it is unstable.

Original content - 200g

1 half life - 100 g
2 half life - 50 g
3 half life - 25 g

The correct solution would be D. 25 g.
3 0
3 years ago
The _______ is a factor that's affected by changes in the independent variable.
zloy xaker [14]
The answer to your question is dependent variable. 
6 0
3 years ago
Answer these please! 23 points!
Aleksandr-060686 [28]

For the first question the answer is

The "s" orbital can only hold a maximum of two electrons. ... Elements in the each group have the same number of valence electrons. Why is hydrogen set apart by itself? Hydrogen does not belong to a single group b/c it can be considered an alkali metal, but it is also a gas.

8 0
3 years ago
A given mass of air has a volume of 6.00 L at 101 kPa. At constant temperature, the pressure is decreased to 25.0 kPa. Calculate
GenaCL600 [577]

Answer:

24.24 L

Explanation:

Boyle’s law, also called Mariotte’s law, a relation concerning the compression and expansion of a gas at constant temperature.

This empirical relation, formulated by the physicist Robert Boyle in 1662, states that the pressure (p) of a given quantity of gas varies inversely with its volume (v) at constant temperature; i.e., in equation form, pv = k, a constant.

Real gases obey Boyle’s law at sufficiently low pressures, although the product pv generally decreases slightly at higher pressures, where the gas begins to depart from ideal behaviour.

As, PV = k

P₁ V₁ = P₂ V₂

Given P₁ = 101 KPa

V₁ = 6 L

P₂ = 25 kPa

So, V₂ = P₁ V₁ /P₂ = 101 *6/25 = 24.24 L

4 0
3 years ago
A solution of [FeSCN]^{2+} is found to have 37% transmittance at 447 nm. If the molar absorption coefficient (ε) is 4400 at λ_{m
alexandr1967 [171]

Answer:9.81×10^-5 M

Explanation: See attachments

8 0
4 years ago
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