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likoan [24]
3 years ago
9

A type of plate boundary that is transform faults (easily seen where they cut at right angles to the mid-ocean ridges) A.) conve

rgent B.) transform C.) divergent
Chemistry
1 answer:
34kurt3 years ago
8 0
The answer is Option C (Divergent Plate Boundary)

Mapping efforts have shown that mid-ocean ridges<span> are discontinuous structures that cut at </span>right angles<span> to its length at various transform faults. They typically </span><span>demarcate the </span>boundary <span>between two tectonic plates, and are therefore called </span>divergent<span> plate </span>boundaries.
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Select the correct answer.
Fittoniya [83]

Answer:

subscribe to me on you-tube for brainliest custom link since u cant do a you-tube link :/

https://screenshare.host/B7N8NT

Explanation:

7 0
2 years ago
A 30ml sample of a liquid has a mass of 50 grams. What is the density of the liquid?
mash [69]

Answer:

<h2>Density = 1.67 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass = 50 g

volume = 30 mL

Substitute the values into the above formula and solve for the density

That's

Density =  \frac{50}{30}  \\  =  \frac{5}{3}  \\  = 1.66666...

Wr have the final answer as

<h3>Density = 1.67 g/mL</h3>

Hope this helps you

5 0
3 years ago
How do strong southerly winds affect the vapor pressure?
dedylja [7]

Answer:

An increase

Explanation:

The strong southerly winds affect the vapor pressure by increasing it .

When the vapor pressure increases it means an increase in temperature and more evaporation occurs.

A decrease in the vapor pressure means a reduction in temperature with less amount of evaporation being involved

5 0
3 years ago
For the following electron-transfer reaction:
creativ13 [48]

Answer:

1. The oxidation half-reaction is: Mn(s) ⇄ Mn²⁺(aq) + 2e⁻

2. The reduction half-reaction is: Ag⁺(aq) + 1e⁻ ⇄ Ag(s)  

Explanation:

Main reaction: 2Ag⁺(aq) + Mn(s) ⇄ 2Ag(s) + Mn²⁺(aq)

In the oxidation half reaction, the oxidation number increases:

Mn changes from 0, in the ground state to Mn²⁺.

The reduction half reaction occurs where the element decrease the oxidation number, because it is gaining electrons.

Silver changes from Ag⁺ to Ag.

1. The oxidation half-reaction is: Mn(s) ⇄ Mn²⁺(aq) + 2e⁻

2. The reduction half-reaction is: Ag⁺(aq) + 1e⁻ ⇄ Ag(s)  

To balance the hole reaction, we need to multiply by 2, the second half reaction:

Mn(s) ⇄ Mn²⁺(aq) + 2e⁻

(Ag⁺(aq) + 1e⁻ ⇄ Ag(s)) . 2

2Ag⁺(aq) + 2e⁻ ⇄ 2Ag(s)  

Now we sum, and we can cancel the electrons:

2Ag⁺(aq) + Mn(s) + 2e⁻ ⇄ 2Ag(s) + Mn²⁺(aq) + 2e⁻

4 0
3 years ago
In our simulation what did the σ (sigma) stand for?
soldier1979 [14.2K]

Answer:

C -The atomic radius

Explanation:

I took the test :)

6 0
3 years ago
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