Wavelength = (speed) / (frequency)
Wavelength = (330 m/s) / (1320/s)
Wavelength = (330/1320) m
Wavelength = 0.25 m
<em>Wavelength = 25 cm</em>
The resultant of the acceleration can be found using:
a = √(ax² + ay²)
a = √(1.5² + 3.7²)
a = 3.99 m/s²
v = u + at, u = 0
v = 3.99 x 6.4
v = 25.5 m/s
Vevdbdb
Fxyodupfigigifoydyodoyfpufpuinthrfbfbrhrbrbrthththtbtbyby
Electric current is the movement of electrons through a wire. Electric current is measured in amperes (amps) and refers to the number of charges that move through the wire per second.
Answer:
The magnitude of the net gravitational force exerted by these objects on a 42.0-kg object is 1.818 x 10⁻⁷ N
Explanation:
Given;
first object with mass, m₁ = 285 kg
second object with mass, m₂ = 585 kg
distance between the two objects, r = 4.3 m
The midpoint between the two objects = r/₂ = 4.3 /2 = 2.15 m
Gravitational force between the first object and the 42 kg object;
where;
G = 6.67 x 10⁻¹¹ Nm²kg⁻²
Gravitational force between the second object and the 42 kg object
Magnitude of net gravitational force exerted on 42kg object;
F = 3.545x 10⁻⁷ N - 1.727 x 10⁻⁷ N
F = 1.818 x 10⁻⁷ N
Therefore, the magnitude of the net gravitational force exerted by these objects on a 42.0-kg object is 1.818 x 10⁻⁷ N