What is the average total energy density in electromagnetic radiation that has an intensity of 475 W/m^2?
1 answer:
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The period of a pendulum is given by
where L is the pendulum length and g is the gravitational acceleration.
We can write down the ratio between the period of the pendulum on the Moon and on Earth by using this formula, and we find:
where the labels m and e refer to "Moon" and "Earth".
Since the gravitational acceleration on Earth is
while on the Moon is 
, the ratio between the period on the Moon and on Earth is
where L is the pendulum length and g is the gravitational acceleration.
We can write down the ratio between the period of the pendulum on the Moon and on Earth by using this formula, and we find:
where the labels m and e refer to "Moon" and "Earth".
Since the gravitational acceleration on Earth is
Solution :
Given data :
Mass of the merry-go-round, m= 1640 kg
Radius of the merry-go-round, r = 7.50 m
Angular speed, rev/sec
rad/sec
= 5.89 rad/sec
Therefore, force required,
= 427126.9 N
Thus, the net work done for the acceleration is given by :
W = F x r
= 427126.9 x 7.5
= 3,203,451.75 J