Answer:
the minimum value of the coefficient of static friction between the ground and the cheetah's feet is 1.94
Explanation:
Given that ;
the top speed of Cheetahs is almost 60 mph
In cornering abilities ; the maximum centripetal acceleration of a cheetah was measured to be = 19 m/s^2
The objective of this question is to determine the what minimum value of the coefficient of static friction between the ground and the cheetah's feet is necessary to provide this acceleration?
From the knowledge of Newton's Law;
we knew that ;
Force F = mass m × acceleration a
Also;
The net force 
= frictional force 
so we can say that;
m×a =
where;
the coefficient of static friction 
is:
= 1.94
Hence; the minimum value of the coefficient of static friction between the ground and the cheetah's feet is 1.94
Answer:
Let us develop the transformation of force from a system S where a particle is moving at a speed v to any system S' which is moving relative to system S at a speed V. ...
Explanation:
hope it works out
<h2>
Answer: Pulsars</h2>
A <u>pulsar</u> is a neutron star that emits very intense electromagnetic radiation at short and periodic intervals ( rotating really fast) due to its intense magnetic field that induces this emission.
Nevertheless, it is important to note that all pulsars are neutron stars, but not all neutron stars are pulsars.
Let's clarify:
A neutron star, is the name given to the remains of a supernova. In itself it is the result of the gravitational collapse of a massive supergiant star after exhausting the fuel in its core.
Neutron stars have a small size for their very high density and they rotate at a huge speed.
However, the way to know that a pulsar is a neutron star is because of its high rotating speed.
Answer:
1629 metres
Explanation:
Given that Carlos runs with velocity v = (5.6 m/s, 29o north of east) for 10 minutes.
To the north, the velocity will be:
V = 5.6 × sin 29
V = 2.715 m/s
Convert the time to second
Time = 10 × 60 = 600
Using the formula below
Velocity = distance/ time
Substitute all the parameters into the formula
2.715 = distance/600
Distance = 2.715 × 600
distance = 1629 m
plastics, Styrofoam hOPE THIS HELPS
