All categories

2 years ago

Which conditions are usually the effect of a low air pressure system?

Physics

2 answers:

alukav5142 [94]2 years ago

8 0

Answer:

cloudy and wet weather

Umnica [9.8K]2 years ago

3 0

Explanation : High air pressure is generally associated with nice weather.

Low air pressure is generally associated with cloudy, rainy, or snowy weather.

Therefore, Cloudy and wet weather .

You might be interested in

A 46.0-kg box is being pushed a distance of 8.80 m across the floor by a force P whose magnitude is 171 N. The force P is parall

dolphi86 [110]

Answer:

a) 1504.8 J

b) 991.76 J

c) 0J

d) 0J

Explanation:

(a) The work done by the force P on the box is given by the following formula:

$W_P=Px$

P: applied force = 171N

x: distance in which the for P is applied = 8.80m

you replace the values of P and x and obtain:

$W_P=(171N)(8.80m)=1504.8J$

(b) The work don by the friction force is:

$W_f=F_fx=\mu N x=\mu Mg x$

μ = coefficient of kinetic friction = 0.250

M: mass of the box = 46.0kg

g: gravitational constant = 9.8 m/s^2

$W_f=(0.250)(46.0kg)(9.8m/s^2)(8.80m)=991.76J$

$N=Mg=(46.0kg)(9,8m/s^2)=450.8N$

but this force does not do work on the box because the direction is perpendicular to the direction of the force P.

$W_N=0J$

(d) the same as before:

$W_g=0J$

8 0

2 years ago

Delilah does 170 Joules of work in 30 seconds. Adam does 260 Joules of work in 20 seconds. Who was more powerful?

sp2606 [1]

Power = $\frac{Work}{Time}$

Delilah: 170J/30s = 5.66 W

Adam: 260J/20s = 13 W

6 0

2 years ago

A proton is projected perpendicularly into a magnetic field that has a magnitude of 0.50 T. The field is then adjusted so that a

bixtya [17]

Answer:

$B_e = 2.72 \times 10^{-4} T$

Explanation:

As we know that when charge particle is projected in perpendicular magnetic field then the radius of the charge particle is given as

$F = qvB$

$\frac{mv^2}{r} = qvB$

now we have

$r = \frac{mv}{qB}$

since here radius of proton and electron will be same

so we will have

$r_e = r_p$

$\frac{m_e v}{q_e B_e} = \frac{m_p v}{q_p B_p}$

so we have

$B_e = \frac{B_p m_e}{m_p}$

given that

$B_p = 0.50 T$

$m_e = 9.11 \times 10^{-31} kg$

$m_p = 1.67 \times 10^{-27} kg$

so we have

$B_e = \frac{0.50(9.11\times 10^{-31})}{1.67\times 10^{-27}}$

$B_e = 2.72 \times 10^{-4} T$

4 0

2 years ago

Read 2 more answers

There are great similarities between electric and gravitational fields. A room can be electrically shielded so that there are no

ella [17]

Answer:

Can a room be gravitationally shielded? No, it can't.

Explanation:

the room cannot be gravitationally shielded because there is only one gravitational charge, in this case is mass. Mass can always be positive. the room can be electrically shielded because there are two type of charge, positive and negative charge than can cancel each other out.

7 0

2 years ago

7. A spring balance reads force in Newton. The scale is 20 cm long and reads from 0 to

GarryVolchara [31]

Answer:

The potential energy when it reads 40 N is $PE = 5.33 \ J$