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3 years ago

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a block (mass 0.6kg) is released from rest at point A at the top of a ramp inclined at 36.9 degress above the horizontal. The bl

ock moves a distance of 4m along the ramp to point b at the bottom of the ramp. How much work is done by gravity as the block goes from a to b

1 answer:

bija089 [108]3 years ago

3 0

14.136 J as shown on the photo with two thought processes but overall same calculation

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Based on relative bond strengths, classify these reactions as endothermic (energy absorbed) or exothermic (energy released)

cluponka [151]

<span>Exothermic reaction is a chemical reaction that releases energy. This reaction releases heat energy or light . In an endotermic reaction energy is used. Enthaply is the heat energy change , delta H. If the sum of the enthalpies of the reactans is greater than the products the reaction is exothermic. If the products side has a larger enthaply than the process is endothermic. So, if delta H is negative then the process is exothermic. If delta H is positive, than the process is endothermic. Exothermic are: A+BC -> AB+C A2+B2 -> 2AB Endothermic are:AB+C -> AC+B A2 + C2 -> 2AC B2+C2 -> 2BC</span>

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3 years ago

2. A hanging wind-chime on a calm day would have kinetic or potential energy?

rjkz [21]

Answer:

it would have potential energy

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3 years ago

Canned vegetables are usually more expensive than fresh vegetables true or false

aalyn [17]

Answer:

Explanation:

true because i depends (what market you go to) and how much the vegetable weighs

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A rubber ball that sits motionless near the edge of a tall bookshelf has no kinetic energy. However, it does have mechanical

klio [65]

It is possible because the rubber ball has mechanical energy which is equal to potential energy.

<h3>What is mechanical energy?</h3>

Mechanical energy of an object is the total energy possessed by the object, including the potential energy and the kinetic energy.

M.A = K.E + P.E

<h3>What is kinetic energy?</h3>

Kinetic energy is the energy possessed by an object due to its motion.

<h3>What is potential energy?</h3>

Potential energy is the energy possessed by an object due to its position.

When kinetic energy (K.E) = 0

M.A = P.E

Thus, it is possible because the rubber ball has mechanical energy which is equal to potential energy.

Learn more about mechanical energy here: brainly.com/question/24443465

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3 years ago

In a local bar, a customer slides an empty beer mug down the counter for a refill. The height of the counter is 1.42 m. The mug

telo118 [61]

Answer:

a) $V_{x}=3.72m/s$ , b) ∠=-54.83°

Explanation:

In order to solve this problem, we must start with a drawing of the situation, this will help us visualize the problem better. (See picture attached).

a)

Now, the idea is that the beer mug has a horizontal speed and no vertical speed at initial conditions. So knowing this, we can start finding the initial velocity of the mug.

In order to do so, we need to find the time it takes for the mug to reach the ground. We can find it by using the following equation:

$y=y_{0}+V_{y0}t+\frac{1}{2}a_{y}t^{2}$

We can see from the drawing that y and the initial velocity in y are zero, so we can simplify our formula:

$0=y_{0}+\frac{1}{2}a_{y}t^{2}$

so we can solve for t, so we get:

$t=\sqrt{\frac{-(2)y_{0}}{a}}$

so now we can substitute the known values, so we get:

$t=\sqrt{\frac{-(2)(1.42)}{-9.8}}$

which yields:

t=0.538s

So we can use this value to find the velocity in x:

$V_{x}=\frac{x}{t}$

When substituting we get:

$V_{x}=\frac{2m}{0.538s}$

which yields:

$V_{x}=3.72m/s$

b)

In order to solve part b, we need to find the y-component of the velocity, for which we can use the following formula:

$\Delta y=\frac{V_{f}^{2}-V_{0}^{2}}{2a}$

We know that $V_{0}$ is zero, so we can simplify the expression:

$\Delta y=\frac{V_{yf}^{2}}{2a}$

So we can solve the equation for $V_{yf}^{2}$ so we get:

$V_{yf}=\sqrt{2\Delta y a}$

and when substituting the known values we get:

$V_{yf}=\sqrt{2(-1.42m)(-9.8m/s^{2})}$

which yields:

$V_{yf}=-5.28m/s$

Once we got the final velocity in y, we can use it together with the velocity in x to find the angle.

So we can use the following formula:

$tan \theta =\frac{V_{y}}{V_{x}}$

when solving for theta we get:

$\theta = tan^{-1}(\frac{V_{y}}{V_{x}})$

We can substitute so we get:

$\theta = tan^{-1}(\frac{-5.28m/s}{3.72m/s})$

which yields:

$\theta = -54.83^{o}$

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3 years ago