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Kipish [7]
4 years ago
9

A step up transformer used in an automobile has a potential difference across the primary of 1800 V and a potential difference a

cross the secondary of 12 V. What is the ratio of the number of turns of wire on the primary to the number of turns on the secondary?
Physics
1 answer:
Zepler [3.9K]4 years ago
5 0
Please don't use a car's ignition coil as an example. Let's just say it's an ordinary transformer. If you connect 1800 volts AC to one side of the transformer and you get 12 volts out of the other side, then the turns of wire are in the same ratio as the voltages ... 1800/12 = 150.
A car coil doesn't work like an ordinary transformer. In a car, you put 12-volt pulses into one side, and you get voltage out of the other side that's high enough to fire spark plugs and ignite gasoline.
So you've actually got the primary and secondary windings labeled in reverse in the question, and you're actually using it as a step-DOWN transformer.
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More massive objects have a large gravitational force or weight. Why do heavier objects accelerate to the ground at the same rat
8090 [49]

Answer:

D) Heavier objects need a greater force to accelerate according to F=ma.

Explanation:

The force of gravity acting on an object is equal to:

F = mg

where m is the mass of the object and g is the acceleration due to gravity. According to the formula, heavier objects (objects with greater mass, m) have a larger force of gravity acting on them.

However, the acceleration of an object towards the ground is given by:

a=\frac{F}{m}

therefore, we see that if the object is heavier (larger mass, m), the force of gravity (F) must also be larger in order to have the same acceleration a.

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3 years ago
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The snow fell on me is my excuse so my mom won’t know that I’m getting bullied
larisa [96]

Answer:

Aaaaw noooo. :(

Explanation:

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7 0
3 years ago
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A dog walks 8.0 meters due north and then 6.0 meters due east. Determine the magnitude of the dog's total displacement to the ne
Rus_ich [418]

Answer:

the magnitude of the dog's total displacement to the nearest tenths = 53.12°

Explanation:

Given that:

a dog walks 8.0m due to the north and 6.0 m due east.

We can determine the magnitude of the dog's total displacement by using the Pythagoras theorem.

Consider the north direction be the opposite and the east direction to be the adjacent, therefore the hypotenuse will be the dog's total displacement.

So, suppose hypotenuse is represented by a

the opposite represented by b, and the adjacent represented by c

Then;

a² = b² + c²

a² = 8²  +  6²

a² = 64 + 46

a² = 100

a =\sqrt{100

a = 10.0 m

However, the magnitude of the dog's total displacement is calculated by taking the tangent of the system.

tan θ = opposite / adjacent

tan θ = b/c

tan θ = 8/6

tan θ = 4/3

tan θ = 1.333

θ = tan⁻¹ (1.333)

θ = 53.12

the magnitude of the dog's total displacement to the nearest tenths = 53.12°

6 0
3 years ago
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4 years ago
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Answer:

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b )

If we go deep inside the planet to get force on apple equal to .3 F_R

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.3 F_R = G  4/3 π ( R - h ) d m

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F_R  = G 4/3πR³d m / R²

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dividing two equations

0.3 =  ( R - h ) / R

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7 0
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