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egoroff_w [7]
4 years ago
5

What type of waves can only travel through a medium?

Physics
2 answers:
scoray [572]4 years ago
7 0

<u>Answer:</u> The waves that travel through a medium is electromagnetic waves.

<u>Explanation:</u>

There are two types of waves:

  • <u>Electromagnetic waves:</u> These are waves which can travel through vacuum. These have electrical and magnetic component associated with them. They travel with the speed of light. They does not require a medium to travel. For Example: Infrared waves, Microwaves
  • <u>Mechanical waves:</u> These are the waves that require a medium to travel so that they can transport their energy from one location to another. For Example:  Sound waves

Hence, the waves that travel through a medium is electromagnetic waves.

katovenus [111]4 years ago
5 0

Answer:

The energy of a mechanical wave can travel only through matter. The matter through which the wave travels is called the medium (plural, media). The medium in the water wave pictured above is water, a liquid. But the medium of a mechanical wave can be any state of matter, even a solid.Nov 1, 2012

Explanation:

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An ordinary flashlight uses two D cells 1.50 V batteries connected in series. The bulb draws 380 m???? when turned on.
melamori03 [73]

Answer:

a. 7.89 Ω, 1.14 W

b. By a factor of 2; The batteries would heat up.

Explanation:

a. Using Ohm's law, we have that Voltage, V, is directly proportional to Current, I, with the constant of proportionality being Resistance, R. Mathematically:

V = IR

The voltage of the two batteries would be:

V = V1 + V2 = 1.5 + 1.5 = 3.0 V

The current is 380 mA = 0.38 A

Hence, the Resistance, R, will be:

R = \frac{V}{I}

R = \frac{3}{0.38}

R = 7.89 Ω

Power is given as:

P = IV

P = 3 * 0.38

P = 1.14 W

b. If the batteries are now 4, the new voltage will be:

V = 4 * 1.5

V = 6 V

Power becomes:

P = 0.38 * 6

P = 2.28 W

Comparing with Power in (a) above, we see that the new Power is double the value of the former Power. Hence, the Power has increased by a factor of 2.

It is not advisable to use double the number of batteries to power a flashlight because it would cause the batteries to heat up and thereby, leak or in the worst case scenario, blow up. This could be damaging to the flashlight.

3 0
3 years ago
What object is shown below? ASAP
fgiga [73]

The object shown is a convex mirror. A convex mirror has a reflective surface and the body of it is curved outwards, it is used in sunglasses, security areas, telescopes, and magnifying glass.




5 0
3 years ago
Read 2 more answers
Which chemical equation correctly shows the formation of water from hydrogen
nekit [7.7K]

Answer:

d. H + O2 ------ H2O

that's the formation of water

6 0
3 years ago
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If a galaxy has an apparent radial velocity of 2000 km/s and the Hubble constant is 70 km/s/Mpc, how far away is the galaxy
ddd [48]

Answer:

28.57 Mpc

Explanation:

This question is going to be solved by applying Hubble's Law.

This Hubble's Law is actually an observation in physical cosmology. This observation makes it clear that galaxies are moving away from the Earth, and are doing so at speeds proportional to their distance. This essentially means that the farther they are from the Earth, the faster they are moving away from Earth.

It is represented by this formula

v = H(0)D, where

v = speed

H(0) = Constant of proportionality, or otherwise, Hubble's constant.

D = Distance to a galaxy

Applying the given parameters to the formula, we have

v = H(0).D

D = v / H(0)

D = 2000 / 70

D = 28.57 Mpc

3 0
3 years ago
Two masses are joined by a mass less string. A 33-N force applied vertically to the upper mass gives the system a constant upwar
lisov135 [29]

Lower mass: 1.20 kg, upper mass: 1.28 kg

Explanation:

In order to solve the problem, we consider the forces acting on the upper mass only first.

The upper mass is acted upon three forces:

  • The applied force F_a=33 N, upward
  • The weight of the mass itself, m_u g, where m_u is the upper mass and g=9.8 m/s^2 is the acceleration of gravity, downward
  • The tension in the string, T=16 N, downward

Therefore, the equation of the forces for the upper mass is:

F_a - m_u g - T = m_u a

where

a=3.5 m/s^2 is the acceleration (upward)

Solving for m_u,

m_u = \frac{F_a-T}{a+g}=\frac{33-16}{3.5+9.8}=1.28 kg

Now we can find the lower mass by considering the forces acting on it:

  • The tension in the string, T = 16 N, upward
  • The weight of the mass itself, m_L g, where m_L is the lower mass, downward

So the equation of the forces is

T-m_L g = m_L a

And solving for the mass,

m_L = \frac{T}{a+g}=\frac{16}{3.5+9.8}=1.20 kg

Learn more about acceleration and forces:

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#LearnwithBrainly

7 0
3 years ago
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