A and b is the croccet answer sir hope it helps
Answer:
The vacuum would stop
Explanation:
if the lid opened the there would be no more pressure therefor no vacuum.
Answer:
3.1 moles of ammonia
18.67× 10²³ molecules
Mass = 52.7 g
Explanation:
Given data:
Number of atoms of hydrogen = 5.68×10²⁴ atoms
A) Number of molecules of ammonia = ?
Solution:
First of all we will calculate the number of moles of hydrogen.
1 mole = 6.022× 10²³ atoms
5.68×10²⁴ atoms × 1 mol / 6.022× 10²³ atoms
0.94×10¹ mol
9.4 moles of hydrogen
Moles of ammonia:
3 moles of hydrogen are present in one mole of ammonia.
9.4 moles of hydrogen = 1/3×9.4 =
3.1 moles of ammonia
Number of molecules of ammonia:
1 mole contain 6.022× 10²³ molecules.
3.1 mol × 6.022× 10²³ molecules / 1 mol
18.67× 10²³ molecules
c) Mass of sample = ?
Mass = number of moles × molar mass
Mass = 3.1 moles × 17 g/mol
Mass = 52.7 g
Answer:
The percent yield is 66.7%
Explanation:
1. The balanced chemical reaction to obtain carbon dioxide from the methane is:
2. Calculathe the theoretical quantity of carbon dioxide.
As the problem says that the limiting reagent is the methane, all the calculations will be made from this quantity:
3. Calculate the percent yield:
Percent yield = 
Percent yield = 
Percent yield = 66.7%
