Question

The following Venn Diagram shows the results of a teacher survey. A teacher asked her class which students owned android phones, which owns iPhones, and which had service with AT&T. What is the probability of randomly selecting a student from the class that owns an Android Phone OR had service with AT&T.
Group of answer choices

iphone-5
AT&T-2
Android- 6
IPhone and AT&T-6
AT&T and Android- 6
none- 7


0.60
0.73
0.78
0.46

Answer 1

Answer:

There's a probability of 0.60 to select a student that owns an Android Phone or has service with AT&T.

Step-by-step explanation:

The image attached shows the Venn Diagram.

From the diagram, 12 students use AT&T service and 6 students use an Android phone only. The total number of students is 30.

The probability to pick a student with Android is

$P_{android}=\frac{6}{30}=0.2$

The probability to pick a studen with AT&T is

$P_{AT\&T} =\frac{12}{30}=0.4$

Remeber, the probability of one event OR another implies the sum of probabilities.

$P=0.2+0.4=0.60$

Therefore, there's a probability of 0.60 to select a student that owns an Android Phone or has service with AT&T.

Answer 2

Answer: 0.60

Step-by-step explanation:

30 total students

6 have Androids

6+2+4= 12 had services with AT&T

12+6=18

18/30

3/5 Simplify

0.60 when you divide 3 into 5