<span>2.0 moles. (83.3g / 208 [grams/moles] *5 [from balancing] = around 2 </span>
It is rinsed one last time with the solution to be measured because if there is water in the burret, then it could alter the results. Slightly, but it is still altering it.
Answer:
34 g/100 mL
Explanation:
The solubility of a compound can be expressed in g/100mL, for this we must divide the mass of the compound that dissolves in the solute by the volume of the solvent.
The solvent, in this case, is water, and that mass of the solute X that dissolved is the mass that was recovered after the solvent was drained and evaporated. So the solubility of X (S) is:
S = 0.17 kg/5L
S = 170g/5000mL
S = 170g/(5*1000)mL
S = 34 g/100 mL
Phương trình hóa học: 2Mg+O2->2Mgo
P x V = n x R x T
P x 73 = 2.97 x 0.082 x 298
P x 73 = 72.57492
P = 72.57492 / 73
P = 1.0 atm
hope this helps!