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Katen [24]
2 years ago
6

Imagine a rock comprised entirely of an unstable isotope. After three half-lives, how much of the parent isotope remains

Chemistry
1 answer:
uysha [10]2 years ago
7 0

Answer:  After three half-lives 1/8 (12.5%) of the original sample remains

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ILL GIVE BRAINLY, 5 STARS , FOLLOW AND HEARTS
Jlenok [28]

Answer:

Second one

Explanation:

I think it's the second cause there's no energy w/o heat. So it's the second.

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3 years ago
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What are the units of molar mass?<br> O A. Lig<br> O B. g/mol<br> O c. g/L<br> O D. mol/g
Lorico [155]
The units of molar mass is g/mol that is the letter B.
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3 years ago
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Many enzymes are inhibited irreversibly by heavy metal ions such as Hg2+ , Cu2+ , or Ag+ , which can react with essential sulfhy
3241004551 [841]

Answer:

The minimum molecular weight of the enzyme is 29.82 g/mol

Explanation:

<u>Step 1:</u> Given data

The volume of the solution = 10 ml = 10*10^-3L

Molarity of the solution = 1.3 mg/ml

moles of AgNO3 added = 0.436 µmol = 0.436 * 10^-3 mmol

<u>Step 2:</u> Calculate the mass

Density = mass/ volume

1.3mg/mL = mass/ 10.0 mL

mass = 1.3mg/mL *10.0 mL = 13mg

<u>Step 3:</u> Calculate minimum molecular weight

Molecular weight = mass of the enzyme / number of moles

Molecular weight of the enzyme = 13mg/ 0.436 * 10^-3 mmol

Molecular weight = 29.82 g/mole

The minimum molecular weight of the enzyme is 29.82 g/mol

7 0
4 years ago
Write the formula for the conjugate base for the following acids. <br>Thank you ​
Llana [10]

Answer:

See the answer and explanation below , please.

Explanation:

A conjugate base is defined as that formed after an acid donates its proton.

For each article, a continuation of the conjugate bases (highlighted in bold), for dissociation in water:

a) HF + H20 --> F- + H30+      

b) H20+ H20 --> OH-  + H30+

C)H2PO3-  + H20--> HPO3 2-   + H30+

d) HSO4- + H20 -->  SO4 2- + H30+

E) HCL02 + H20 --> CLO02 -   + H30+

7 0
4 years ago
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At a certain temperature, the solubility of strontium arsenate, Sr3(AsO4)2, is 0.0540 g/L. What is the Ksp of this salt at this
blondinia [14]
 <span>Get into moles first. .0590 grams over 540.8 grams per mole = 1.09 x l0^-4 moles 

Sr3(As04)2 = 3 Sr++(aq) plus 2 As04^-3(aq) 

Ksp = (Sr++)^3(As04^-3)^2 

(Sr++) = 3 X l.09 x l0^-4 = 3.27 x l0^-4 

(As04^-3) = 2 x l.09 x l0^-4 = 2.18 x l0^-4 

<span>Ksp = (3.27 x l0^-4)^3 (2.18 x l0^-4)^2 which equals 1.66 x 10^-18th


I hope my answer has come to your help. Thank you for posting your question here in Brainly.</span></span>
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