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mars1129 [50]
3 years ago
6

Please help 100 point s

Chemistry
2 answers:
ki77a [65]3 years ago
5 0
Where is the chart?????
Anni [7]3 years ago
5 0

air is NOT a compound - it is a mixture of different gases like O2, N2 n CO2. CO2 is a pure substance but NOT an element. so the CORRECT ans is


C) The chart shows the percentages of pure substances in a mixture.


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Using the method of initial rates for the reaction a → b, if the initial concentration of a is doubled and the rate of reaction
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In which state of matter does heat travel fastest and slowest?
MariettaO [177]

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Heat travels faster in solids.

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Explanation:

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2 years ago
How many significant figures does 0.005505 have
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Assume that silver and gold form ideal, random mixtures. Calculate the mass of pure Ag needed to cause an entropy increase of 20
KengaRu [80]

Answer:

m_{Ag}=2,265.9g

Explanation:

Hello!

In this case, since the definition of entropy in a random mixture is:

\Delta S=-n_TR\Sigma[x_i*ln(x_i)]

For this silver-gold mixture we write:

\Delta S=-(n_{Au}+n_{Ag})R\Sigma[\frac{n_{Au}}{n_{Au}+n_{Ag}} *ln(\frac{n_{Au}}{n_{Au}+n_{Ag}} )+\frac{n_{Ag}}{n_{Au}+n_{Ag}} *ln(\frac{n_{Ag}}{n_{Au}+n_{Ag}} )]

By knowing the moles of gold:

n_{Au}=100g*\frac{1mol}{197g} =0.508mol

It is possible to write the aforementioned formula in terms of the variable x representing the moles of silver:

20\frac{J}{mol}=-(0.508+x)8.314\frac{J}{mol*K} \Sigma[\frac{0.508}{0.508+x} *ln(\frac{0.508}{0.508+x} )+\frac{x}{0.508+x} *ln(\frac{x}{0.508+x} )]

Which can be solved via Newton-Raphson or a solver software, in this case, I will provide you the answer:

x=n_{Ag}=21.0molAg

So the mass is:

m_{Ag}=21.0mol*\frac{107.9g}{1mol}\\ \\m_{Ag}=2,265.9g

Best regards!

3 0
2 years ago
Please help, will give the brainiest answer
iren2701 [21]

Answer:

Ag+Nano3 yes

MN + Cao.?No

8 0
2 years ago
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