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2 answers:
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Answer: The correct option is (c). The total pressure doubles.
Solution:
Initially, only 4 moles of oxygen gas were present in the flask.
(
) ( according to Dalton's law of partial pressure)
....(1)
= Total pressure when only oxygen gas was present.
Final total pressure when 4 moles of helium gas were added:
partial pressure of oxygen in the mixture :
Since, the number of moles of oxygen remains the same, the partial pressure of oxygen will also remain the same in the mixture.
= Total pressure of the mixture.
from (1)
On rearranging, we get:
The new total pressure will be twice of initial total pressure.
Answer:
2.73 is the equilibrium constant for the dissociation of gas at 840 degree Celsius.
Explanation:
Initial
0.600 atm 0
Equilibrium
(0.600 atm - p) 2p
Total pressure at equilibrium = P = 0.984 atm
P= 0.600 atm - p)+2p=0.984 atm
p = 0.384 atm
Partial pressure of the gas ,
= (0.600 atm - 0.384 atm)=0.216 atm
Partial pressure of the gas,
= 2(0.384 atm)=0.768 atm
2.73 is the equilibrium constant for the dissociation of gas at 840 degree Celsius.