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2 years ago

Which equation can be used to solve for I in the following diagram?

Mathematics

1 answer:

vaieri [72.5K]2 years ago

4 0

The answer is the the 3rd option! Hope this helps!

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4. Solve the following system of equations for x.

Ber [7]

We are given the system of equations -:

$\large{ \begin{cases} 2x + 3y = - 14 \\ y = 6x + 22 \end{cases}}$

Since the second equation is y-isolated equation. It can be substituted as y = 6x+22 in the first equation.

$\large{2x + 3(6x + 22) = - 14}$

Expand 3 in the expression so we can combine like terms and isolate x-variable.

$\large{2x + 18x + 66 = - 14}$

Then combine like terms.

$\large{20x + 66 = - 14}$

Get rid of 66 from the left side by subtracting both sides by itself.

$\large{20x + 66 - 66 = - 14 - 66} \\ \large{20x = - 80}$

To finally isolate the variable, divide both sides by 20 so we can leave x only on the left side.

$\large{ \frac{20x}{20} = \frac{ - 80}{20} }$

Simplify to the simplest form.

$\large{x = - 4}$

Normally, we have to find the y-value too but since we only find x-value. The answer is x = -4.

Answer

x = -4

I hope this helps! If you have any questions or doubts regarding my answer, explanation or system of equations, feel free to ask!

5 0

2 years ago

Elsie and her friends plan to drive 1048 miles during their road trip. How many gallons of gas will they need for this trip?

ElenaW [278]

That would depend on the car and the amount of miles the car can go on one tank of gas. Divide that amount from 1048 to get the answer.

3 0

3 years ago

You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta

vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

$m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$m = -\frac{\cos 2\theta}{\sin \theta}$

The tangent line is horizontal when $m = 0$ . Then:

$\cos 2\theta = 0$

$2\theta = \cos^{-1}0$

$\theta = \frac{1}{2}\cdot \cos^{-1} 0$

$\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right)$ , for all $i \in \mathbb{N}_{O}$

$\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}$ , for all $i \in \mathbb{N}_{O}$

The first four solutions are:

x: $\sqrt{2}$ $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$

y: 1 -1 1 -1

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

6 0

2 years ago

Sherry needs $120 by the end of the month. So far, she has only raised one-fourth of the amount that she needs. How much money h

nexus9112 [7]

The answer is C. Hope this helps

4 0

2 years ago

Read 2 more answers

A certain number is added to four result is double

Pavel [41]

4, 4+4 is 8 which is double of 4

3 0

2 years ago