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Nataly [62]
3 years ago
12

When copper oxide is reacted with sulfuric acid, the acid is often gently heated. This is done in order to:

Chemistry
1 answer:
pav-90 [236]3 years ago
7 0
Copper oxide(solid) + Sulphuric Acid (aqueous)-> Copper Sulphate (aqueous)+ Water(liquid)

In equation form:

CuO +H2SO4 -> CuSO4 + H2O

The colour change you will see is black to blue as Copper oxide is usually found as a black powder. Upon the reaction with sulphuric acid it will change to a cyan blue.

If you heat the made solution of copper sulphate, the water will evaporate and you will be left with white anhydrous copper sulphate crystals.
You might be interested in
What is the volume of a 0.1 M HCl solution containing 1.46 moles of HCI?
Natasha_Volkova [10]
N = cv
1.46 = 0.1 x v
v = 1.46/0.1
v = 14.6 (litres if it’s moles per litre)
5 0
3 years ago
According to the following reaction, how many grams of nitrogen monoxide will be formed upon the complete reaction of 31.0 grams
Mumz [18]

23.227 grams of NO is formed upon the complete reaction of 31.0 grams of oxygen gas with excess ammonia.

Explanation:

The balanced chemical equation is:

4NH3 + 5O2 ⇒ 4NO + 6H20

Number of moles will be calculated.

31 grams of oxygen is given

atomic weight of oxygen gas i.e O2 = 32gm/mole

The molar mass of oxygen gas is 32 grams/mole which is equal to one mole of the molecule.

Number of moles (n) = \frac{mass}{atomic mass of one mole of the substance}

                             n=    \frac{31}{32}

                              n = 0.968 moles of oxygen are given for the reaction to occur.

From the balanced chemical equation it can be seen

5 moles of oxygen yielded 4 moles of NO

So, 0.968 moles of oxygen yield x moles of NO

\frac{4}{5} = \frac{x}{0.968 }

4 × 0.968 =5x

x = 0.774 moles of NO will be formed.

To calculate the mass of NO

mass= atomic mass x number of moles

atomic mass of NO is 30.01 grams/mole

putting the values in the formula:

mass = 30.01 x 0.774

          = 23.227 grams of NO is formed.

8 0
3 years ago
The gas phase decomposition of hydrogen peroxide at 400 °C
Flura [38]

Answer:

t = 71.3 s

Explanation:

Hello there!

In this case, since the second-order integrated law is given by the following equation:

\frac{1}{[H_2O_2]} =\frac{1}{[H_2O_2]_0}+kt

Thus, given the initial and final concentration of hydrogen peroxide and the rate constant, we obtain the following time:

\frac{1}{[0.0170M]}-\frac{1}{0.0800M}=0.650M^{-1}s^{-1}t\\\\t=\frac{46.32M^{-1}}{0.650M^{-1}s^{-1}} \\\\t=71.3s

Best regards!

3 0
2 years ago
What do all akalis have in common
BaLLatris [955]
They all consist of Hydroxide particles (OH)
and they produce hydroxide ions (OH-) when placed in water/aqueous solution.
5 0
3 years ago
In a mixture of volatile substances, the vapor pressure of the solution depends on the vapor pressure of both substances (solute
Alborosie

Answer:

30.4 torr

Explanation:

We have all the information which is required to solve this question ( more than we even need as the molecular weight)

Ptotal = Ptoluene + Pbenzene

Ptotal = Xtoluene Pºtoluene + XbenzenePºbenzene

The mole fraction is given by the formula:

X =number of moles / total number of moles

Xtoluene = 8.53 / (2.15+8.53) = 0.80

Xbenzene = 2.15 / 10.68 = 0.20

⇒Ptotal = 0.80 x 14torr + 0.20 x 96 torr = 30.4 torr

5 0
3 years ago
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