The amount of water that must be added to 6.0 M silver nitrate to make 500mL of 1.2 M solution is : 2000 mL
<u>Given data :</u>
Concentration of siilver nitrate ( M₁ ) = 6.0 M
volume of solution ( V₁ ) = 500 mL
Conc of solution ( M₂ )= 1.2 M
<h3>Determine the amount of water that must be added</h3>
we will apply the equation below
M₁V₁ = M₂V₂ ---- ( 1 )
where : V₂ = V₁ + water added ---- ( 2 )
V₂ ( Final volume ) = ( M₁V₁ ) / M₂
= ( 6 * 500 ) / 1.2
= 2500 mL
Back to eqaution ( 2 )
2500 mL = 500 mL + added water
therefore ; added water = 2500 - 500
= 2000 mL
Hence we can conclude that The amount of water that must be added to 6.0 M silver nitrate to make 500mL of 1.2 M solution is : 2000 mL.
Learn more about Volume : brainly.com/question/12410983
#SPJ1
Answer:
neutrons = atomic mass - atomic number.
hope that helps
C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O
is a combustion reaction
Explanation:
In a combustion reaction a chemical substance (usually organic substances) are reacted with oxygen to form the most stable oxides and heat.
CH₄ + 2 O₂ → CO₂ + 2 H₂O
In a double displacement reaction two compounds exchange elements.
AB + CD → AC + BD
In a decomposition reaction a compound is split into simpler substances.
AB → A + B
In a synthesis reaction two elements are combined to form another compound. A + B → AB
In a single displacement reaction a compound exchange one of its elements.
AB + C → AC + B
Learn more about:
types of chemical reactions
brainly.com/question/314641
#learnwithBrainly
Noble gas configuration for Li : [He]2s¹
<h3>Further explanation
</h3>
In an atom, there are levels of energy in the shell and sub-shell
This energy level is expressed in the form of electron configurations.
Lithium with atomic number 3, then the electron configuration:
1s²2s¹
And for noble gas configuration or it can be called Condensed electron configurations :
[He]2s¹