Answer:

Explanation:
As per energy conservation we can say that during path 1. his initial total mechanical energy must be equal to final total mechanical energy
So we will have

so we will have


Now while he is moving on path 2. then again we can use energy conservation to find the speed



Work is in units of Jules, so any comparison with time is incorrect. Answer D is the definition for velocity, which is incorrect. Answer C is the correct answer
The magnitude of static friction force is f_s = 842.8 N
Explanation:
Write down the values given in the question
The wheel of a car has radius r = 0.350 m
The car applies the torque is τ = 295 N m
It is said that the wheels does not slip against the road surface,
Here we apply a force of static friction,
It can be calculated as
Frictional force f_s = τ / r
= 295 Nm / 0.350 m
f_s = 842.8 N
I believe that the answer is A
Answer:
Gravity
Explanation:
When the ball is falling to the ground, there is only one force- gravity. In some cases, there may be air resistance, but that seems to be neglected here.
Normal force:
Cannot be included. Normal force is only applicable when object is on a surface, and it acts perpendicular to the surface. Since the ball is falling, there is no surface, and therefore no normal force. This question gives you unnecessary information, designed to trick you. Please remember when normal force is applicable.
Friction force:
Also only applicable when object is moving, and is on the table. Friction only applies when there is an applied force. There is no applied force when the ball is falling, so therefore no friction force.
Force of fall:
First of all, what is this? There is nothing called force of fall.
Gravity:
This is the only one that applies. Just draw a vector arrow from the bottom of the ball and label it mg (acceleration due to gravity).