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kupik [55]
3 years ago
5

What causes a solar eclipse? Select all that apply.

Physics
2 answers:
brilliants [131]3 years ago
4 0

I think it is either D) or E)

But i am going to go with E)

kvv77 [185]3 years ago
4 0
B.) the shadow of the moon
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Martine also has an eraser.it has a mass of 3g,and a volume if 1cm3.what is its density
shtirl [24]

Answer:

3g/cm³

Explanation:

<em>Use the formula:</em>

density = mass ÷ volume

<em>Substitute (plug in) the values:</em>

density = 3 ÷ 1 = 3g/cm³

4 0
3 years ago
Boron (B) has an atomic number of 5 and an atomic mass of 11. Boron has _____.
Neko [114]

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the answer is 5 electrons

Explanation:

because its the same name as the amount of protons

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What makes music different from noise?
Zepler [3.9K]

the answers going to be A

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Why are you more likely to get a concussion when hit by a field hockey ball than a
Aleksandr-060686 [28]

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because it can be hard

Explanation:

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3 years ago
A package is dropped from an air balloon two times. In the first trial the distance between the balloon and the surface is Hand
enyata [817]

Answer:

<em>The final speed of the second package is twice as much as the final speed of the first package.</em>

Explanation:

<u>Free Fall Motion</u>

If an object is dropped in the air, it starts a vertical movement with an acceleration equal to g=9.8 m/s^2. The speed of the object after a time t is:

v=gt

And the distance traveled downwards is:

\displaystyle y=\frac{gt^2}{2}

If we know the height at which the object was dropped, we can calculate the time it takes to reach the ground by solving the last equation for t:

\displaystyle t=\sqrt{\frac{2y}{g}}

Replacing into the first equation:

\displaystyle v=g\sqrt{\frac{2y}{g}}

Rationalizing:

\displaystyle v=\sqrt{2gy}

Let's call v1 the final speed of the package dropped from a height H. Thus:

\displaystyle v_1=\sqrt{2gH}

Let v2 be the final speed of the package dropped from a height 4H. Thus:

\displaystyle v_2=\sqrt{2g(4H)}

Taking out the square root of 4:

\displaystyle v_2=2\sqrt{2gH}

Dividing v2/v1 we can compare the final speeds:

\displaystyle v_2/v_1=\frac{2\sqrt{2gH}}{\sqrt{2gH}}

Simplifying:

\displaystyle v_2/v_1=2

The final speed of the second package is twice as much as the final speed of the first package.

5 0
3 years ago
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