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Ierofanga [76]
4 years ago
14

Assume that the Styrofoam slab and the fur are both initially neutral, and that the slab charged negatively after it is rubbed w

ith the fur. Describe what happens. Mark all the correct statements among those provided below. Mark all the correct statements among those provided below.
1. Protons move from the fur to the slab.
2. Protons move from the slab to the fur.
3. Electrons move from the fur to the slab.
4. Electrons move from the slab to the fur.
5. The fur becomes negative after rubbing the slab.
6. The fur becomes positive after rubbing the slab.
7. The fur remains neutral after rubbing the slab.
Physics
1 answer:
BARSIC [14]4 years ago
4 0

Charging phenomenon is basically transfer of electrons from one system to other. When a system loses the electrons the it becomes positively charged and when a system gains electrons then it will become negatively charged

so here if slab is rub against fur then one of them will lose the electrons while other will gain the electrons and hence one will get negatively charged and other will get positive charge

Here it is given that slab get negatively charged so correct options are

<em>3. Electrons move from the fur to the slab. </em>

<em>6. The fur becomes positive after rubbing the slab. </em>

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Answer:

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<em>The question is incomplete:</em>

<em>Which box has the greater acceleration?</em>

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The same applies for the Box B:

a_b=g\frac{(\rho_w-\rho_b)}{\rho_b}

If we express the ratio of the accelerations, we have:

a_a/a_b=\frac{(\rho_w-\rho_a)}{\rho_a}*\frac{\rho_b}{(\rho_w-\rho_b)}\\\\

a_a/a_b=\frac{(\rho_w-\rho_a)}{(\rho_w-\rho_b)} \frac{\rho_b}{\rho_a}

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We will treat the densities as relative to water, so it becomes rho_w=1.

If we distribute the product, and know that the density of B is higher than the density of A, and both are higher than the product of the densities, we have:

\rho_w=1\\\\\frac{a_a}{a_b}=\frac{(1-\rho_a)}{(1-\rho_b)} \frac{\rho_b}{\rho_a}=\frac{\rho_b-\rho_a\rho_b}{\rho_a-\rho_a\rho_b}\\\\\\\rho_b>\rho_a>\rho_a\rho_b>0\\\\\\\frac{a_a}{a_b}=\frac{\rho_b-\rho_a\rho_b}{\rho_a-\rho_a\rho_b}>1\\\\a_a>a_b

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4 years ago
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7 0
3 years ago
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shusha [124]
Shiddd ion even know but can you like my comment?
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3 years ago
"Light traveling in a medium with a refractive index 1.11 is incident on a plate of another medium with index of refraction 1.66
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