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Ierofanga [76]
4 years ago
14

Assume that the Styrofoam slab and the fur are both initially neutral, and that the slab charged negatively after it is rubbed w

ith the fur. Describe what happens. Mark all the correct statements among those provided below. Mark all the correct statements among those provided below.
1. Protons move from the fur to the slab.
2. Protons move from the slab to the fur.
3. Electrons move from the fur to the slab.
4. Electrons move from the slab to the fur.
5. The fur becomes negative after rubbing the slab.
6. The fur becomes positive after rubbing the slab.
7. The fur remains neutral after rubbing the slab.
Physics
1 answer:
BARSIC [14]4 years ago
4 0

Charging phenomenon is basically transfer of electrons from one system to other. When a system loses the electrons the it becomes positively charged and when a system gains electrons then it will become negatively charged

so here if slab is rub against fur then one of them will lose the electrons while other will gain the electrons and hence one will get negatively charged and other will get positive charge

Here it is given that slab get negatively charged so correct options are

<em>3. Electrons move from the fur to the slab. </em>

<em>6. The fur becomes positive after rubbing the slab. </em>

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Please see the picture​
Tpy6a [65]

Answer:

t.f. are you sure that's english? it looks like not a real thing

Explanation:

3 0
3 years ago
A hot air balloon is on the ground, 200 feet from an observer. The pilot decides to ascend at 100 ft/min. How fast is the angle
liq [111]

Answer:

0.0031792338 rad/s

Explanation:

\theta = Angle of elevation

y = Height of balloon

Using trigonometry

tan\theta=y\dfrac{y}{200}\\\Rightarrow y=200tan\theta

Differentiating with respect to t we get

\dfrac{dy}{dt}=\dfrac{d}{dt}200tan\theta\\\Rightarrow \dfrac{dy}{dt}=200sec^2\theta\dfrac{d\theta}{dt}\\\Rightarrow 100=200sec^2\theta\dfrac{d\theta}{dt}\\\Rightarrow \dfrac{d\theta}{dt}=\dfrac{100}{200sec^2\theta}\\\Rightarrow \dfrac{d\theta}{dt}=\dfrac{1}{2}cos^2\theta

Now, with the base at 200 ft and height at 2500 ft

The hypotenuse is

h=\sqrt{200^2+2500^2}\\\Rightarrow h=2507.98\ ft

Now y = 2500 ft

cos\theta=\dfrac{200}{h}\\\Rightarrow cos\theta=\dfrac{200}{2507.98}=0.07974

\dfrac{d\theta}{dt}=\dfrac{1}{2}\times 0.07974^2\\\Rightarrow \dfrac{d\theta}{dt}=0.0031792338\ rad/s

The angle is changing at 0.0031792338 rad/s

6 0
3 years ago
Two states of matter are described below. State A: Cannot be compressed and retains its shape State B: Highly compressible Which
telo118 [61]

Answer:

State A = piece of metal; State B = air

Explanation:

For the three main states of matter here's how it breaks down.

Solid - Cannot be compressed and retains its shape

Liquid - Cannot be compressed and does not retain its shape

Gas - Compressible and does not retain its shape.

Knowing this State A has to be solid.  Only one of the options has A as a solid, so that's the answer.   Worth knowing state B is a gas though, only one compressible, just like solid is the only one that retains its shape.

7 0
4 years ago
Read 2 more answers
An ordinary flashlight battery has a potential difference of 1.2 V between its positive and negative terminals. How much work mu
Maru [420]

The work done to transport an electron from the positive to the negative terminal is 1.92×10⁻¹⁹ J.

Given:

Potential difference, V = 1.2 V

Charge on an electron, e = 1.6 × 10⁻¹⁹ C

Calculation:

We know that the work done to transport an electron from the positive to the negative terminal is given as:

W.D = (Charge on electron)×(Potential difference)

       = e × V

       = (1.6 × 10⁻¹⁹ C)×(1.2 V)

       = 1.92 × 10⁻¹⁹ J

Therefore, the work done in bringing the charge from the positive terminal to the negative terminal is 1.92 × 10⁻¹⁹ J.

Learn more about work done on a charge here:

<u>brainly.com/question/13946889</u>

#SPJ4

4 0
2 years ago
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C. A little backward, 100 or 110 degrees
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