Answer:
The normal force the seat exerted on the driver is 125 N.
Explanation:
Given;
mass of the car, m = 2000 kg
speed of the car, u = 100 km/h = 27.78 m/s
radius of curvature of the hill, r = 100 m
mass of the driver, = 60 kg
The centripetal force of the driver at top of the hill is given as;

where;
Fc is the centripetal force
is downward force due to weight of the driver
is upward or normal force on the drive

Therefore, the normal force the seat exerted on the driver is 125 N.
Answer:
The force is -1620.73 N.
Explanation:
Given that,
Mass of car = 1000 kg
Velocity = 1 m/s
Distance = 2 m
Angle = 30°
We need to calculate the force
Using formula of work done





Put the value into the formula


Hence, The force is -1620.73 N.
Low pressure has a bit less of a function than high pressure, high pressure is more useful in certain terms
Answer:
Distance = displacement = 35m
Explanation:
The distance of the student is how far he has gone.
Distance = 25m + 10m
Distance = 35m
Displacement is the distance specified in specific direction. Since the student walk in the sane direction, thence the displacement is also 35m
Answer:
The input force that you use on an inclined plane is the force with which you push or pull an object. The output force is the force that you would need to lift the object without the inclined plane. This force is equal to the weight of the object.
Explanation: