Energy input remains constant and voltage remains the same in a circuit, but current decreases. Which must be happening?
1 answer:
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Answer:
Explanation:
We are asked to find the final velocity of the boat.
We are given the initial velocity, acceleration, and time. Therefore, we will use the following kinematic equation.
The initial velocity is 2.7 meters per second. The acceleration is 0.15 meters per second squared. The time is 12 seconds.
= 2.7 m/s
- a= 0.15 m/s²
- t= 12 s
Substitute the values into the formula.
Multiply the numbers in parentheses.
Add.
The final velocity of the boat is <u>4.5 meters per second in the positive direction.</u>
Note: I assume the mirror is concave, so that its focal length is positive (it is not specified in the text)
1a) We can use the mirror equation to find the distance of the image from the mirror:
where
is the focal length
is the distance of the object from the mirror
is the distance of the image from the mirror.
Rearranging the equation, we find
so, the distance of the image from the mirror is
.
1b) The image height is given by the magnification equation:
where
is the heigth of the image and 
is the height of the object. By rearranging the equation and using p and q, we find
and the negative sign means the image is inverted.
2) As before, we can find the distance of the image from the mirror by using the mirror equation:
Rearranging it, we find
so, the distance of the image from the mirror is
3) As before, we find the distance of the image from the mirror by using the mirror equation:
Rearranging it, we find
so, the distance of the image from the mirror is
And now we can use the magnification equation to find the image height:
Rearranging it, we find
and the negative sign means the image is inverted.
1a) We can use the mirror equation to find the distance of the image from the mirror:
where
Rearranging the equation, we find
so, the distance of the image from the mirror is
1b) The image height is given by the magnification equation:
where
and the negative sign means the image is inverted.
2) As before, we can find the distance of the image from the mirror by using the mirror equation:
Rearranging it, we find
so, the distance of the image from the mirror is
3) As before, we find the distance of the image from the mirror by using the mirror equation:
Rearranging it, we find
so, the distance of the image from the mirror is
And now we can use the magnification equation to find the image height:
Rearranging it, we find
and the negative sign means the image is inverted.