Answer:
OH⁻ and H₂O
Explanation:
From the equation given in question ,
NH₃ (aq) + H₂O (l) ⇌ NH₄⁺ (aq) + OH⁻ (aq)
Acids are the species which furnish hydrogen ions in the solution or is capable of forming bonds with electron pair species as they are electron deficient species.
When an acid donates a proton, it changes into a base which is known as its conjugate base.
Bases are the species which furnish hydroxide ions in the solution or is capable of forming bonds with electron deficient species as they are electron rich species. When a base accepts a proton, it changes into a acid which is known as its conjugate acid.
The acid and the base which is only differ by absence or presence of the proton are known as acid conjugate base pair.
Hence , from the equation given in the question ,
The conjugate acid - base pair is -
OH⁻ and H₂O
Is that Lr? I'm not sure what the L one stand for?
2:1:1:2
Question 4: The first one
Question 5: The fourth one
Question 6: The first one
Question 7: The third one
Answer: Divide the mass of the object by its volume to yield the density of the object. For example, the object density = mass / (Vf – Vi). Compare the measured density to that of pure gold (19.3 g/cc) to determine whether the object is made of pure gold.
Explanation: I searched it
Answer: it is liquid at most temperatures on earth.
Step-by-step explanation:
